A number smaller than negative infinity in python?

2020-04-10 03:04发布

This is possible in python2:

None < float('-inf')

Also, it always returns

True

However, on python3, this throws

TypeError: unorderable types: NoneType() < int()

Why is None comparable to integers/floats with python2? Are there any benefits or applications to None being orderable in python2?

1条回答
家丑人穷心不美
2楼-- · 2020-04-10 03:39

First of all Python 2 allowed comparing all types of mixed types. This wart was fixed in Python 3 eventually.

CPython implementation detail: Objects of different types except numbers are ordered by their type names; objects of the same types that don’t support proper comparison are ordered by their address.

For None a quick decision was made by Guido and Tim Peters and it resulted in this commit in Python 2.1(emphasis mine):

Part of fixing that was removing some cases of "compare objects of different types by comparing the type name strings". Guido & I were both in the office at the time, and one said to the other: "what about None? Comparing that to other types via comparing the string 'None' doesn't make much sense." "Ya, OK ... how about changing None to - by default - comparing 'less than' objects of other types?" "Don't see why not - sure." "OK, done!

No more than 2 minutes of thought went into it. There was no intent to cater to any real use case here - the only intent was to pick some arbitrary-but-consistent rule that didn't suck quite as badly as pretending None was the string "None" ;-)

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