Numpy has this helper function, np.empty, which will:
Return a new array of given shape and type, without initializing entries.
I find it pretty useful when I want to create a tensor using tf.concat since:
The number of dimensions of the input tensors must match, and all dimensions except axis must be equal.
So it comes in handy to start with an empty tensor of an expected shape. Is there any way to achieve this in tensorflow?
[edit]
A simplified example of why I want this
netInput = np.empty([0, 4])
netTarget = np.empty([0, 4])
inputWidth = 2
for step in range(data.shape.as_list()[-2]-frames_width-1):
netInput = tf.concat([netInput, data[0, step:step + frames_width, :]], -2)
target = tf.concat([target, data[0, step + frames_width + 1:step + frames_width + 2, :]], -2)
In this example, if netInput or netTarget are initialized, I'll be concatenating an extra example with that initialization. And to initialize them with the first value, I need to hack the loop. Nothing mayor, I just wondered if there is a 'tensorflow' way to solve this.
The closest thing you can do is create a variable that you do not initialize. If you use
tf.global_variables_initializer()
to initialize your variables, disable putting your variable in the list of global variables during initialization by settingcollections=[]
.For example,
Here
np.empty
is provided tox
only to specify its shape and type, not for initialization.Now for operations such as
tf.concat
, you actually don't have (indeed cannot) manage the memory yourself -- you cannot preallocate the output as somenumpy
functions allow you to. Tensorflow already manages memory and does smart tricks such as reusing memory block for the output if it detects it can do so.