Recursive tree traversal with mysql through PHP

2020-04-07 03:34发布

I am creating a questionnaire for a client that requires the questions to be organized by 3 layers of levels. I've successfully created the U.I. however I've been trying for the last 3 hours to pull data from a database in such a way that everything loads in the right place. The database is organized like so by the client so I have no control over it:

id    description    parentId    
1      Level 1        0           
2      Level 2        0           
3      Level 1a       1   
4      Level 1b       1 
5      Level 1a1      3      

I have found a similar question to mine on the site but when I attempted it's solution I got the following on repeat infinetly:

Code:

function makeList($par_id = 0) {
    //your sql code here
    $result = mysql_query("SELECT * FROM pB_test WHERE parentId = $par_id");
    $pages = mysql_fetch_array( $result );

    if (count($pages)) {
        echo '<ul>';
        foreach ($pages as $page) {
            echo '<li>', $page['description'];
                makeList($page['parentId']);
                echo '</li>';
        }
        echo '</ul>';
    }
}

makeList();

Output:

1
3
5
5
l
l
3
5
5
l
l
3
5
5
l
l
3
5
5
l
l

Does anyone know how to fix this and what the issue is exactly? Cheers

2条回答
We Are One
2楼-- · 2020-04-07 04:10

it's not good to call mysql server and fetch result each time

what if you have over 100 rows? or 200+

use this to query only once:

$result = mysql_query("SELECT * FROM test");
$arrs = array();

while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
    $arrs[] = $row;
}

function build_tree($arrs, $parent_id=0, $level=0) {
    foreach ($arrs as $arr) {
        if ($arr['parent_id'] == $parent_id) {
            echo str_repeat("-", $level)." ".$arr['name']."<br />";
            build_tree($arrs, $arr['id'], $level+1);
        }
    }
}

build_tree($arrs);

common example for table

  id    name    parent_id
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够拽才男人
3楼-- · 2020-04-07 04:23

Do this recursivly:

function printChildQuestions($parentid) {
  $sql="SELECT * FROM pB_test WHERE parentID=$parentid";
  $result=mysql_query($sql);
  $i=0;
  while (true) {
    $row=mysql_fetch_array($result);
    if (!$row) break;
    if ($i==0) echo "<ul>";
    $i=1;
    echo '<li>'.$row['id'].'&nbsp;'.$row['description'].'&nbsp;'.$row['parentId'].'</li>';
    printChildQuestions($row['id']);
  }
  if ($i>0) echo '</ul>';
}

printChildQuestions(0);
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