How to perform ceiling-division in integer arithme

Question

This question already has answers here:

Is there a ceiling equivalent of // operator in Python? (7 answers)

Closed 4 years ago.

It's basically returning the boxes_needed. 1 box can contain 10 items. So if the items typed by the user is 102 then the code should return 11 boxes.

Is there a way to divide that rounds upwards if there is a non-zero remainder?

Answer 1

Negate before and after?

>>> -(-102 // 10)
11

Answer 2

For your use case, use integer arithmetic. There is a simple technique for converting integer floor division into ceiling division:

items = 102
boxsize = 10
num_boxes = (items + boxsize - 1) // boxsize

Alternatively, use negation to convert floor division to ceiling division:

num_boxes = -(items // -boxsize)

Answer 3

You can try :

import math
math.ceil( x )

Answer 4

from math import ceil

print(ceil(10.3))

11