C++ Declaration and instantiation of scoped variab

Question

I am watching Bjarne Stroustrup's Keynote on C++11 Style (link) (00:35:30) and am having troubles understanding the following (code copied from the slide):

void f(int n, int x)
{
      Gadget g {n};
      // ...
      if (x<100) throw std::run_time_error{"Weird!"};
      if (x<200) return;
      // ...
}

I tried compiling this code using a struct as well as an object but in both cases the compiler tells me that it is expecting a ';' at the end of the declaration of Gadget g and won't compile.

My questions therefore are:

• Am I correct to assume that g is being instantiated?
• What type of object must Gadget be for this code to compile?
• What concept is at work on this line: Gadget g {n};? i.e. What are the curly braces after the declaration?
• (probably too broad, but) Why would the compiler not recognize the curly braces as valid syntax?

Answer 1

Am I correct to assume that g is being instantiated?

Yes, you are correct.

What type of object must Gadget be for this code to compile?

Any type that can be initialized from an int. For instance, if your Gadget class has a constructor taking an int, or taking something that can be initialized directly from an int, that makes the code compile.

What concept is at work on this line: Gadget g {n};? i.e. What are the curly braces after the declaration?

That's uniform initialization syntax. It eliminates some nasty problem with the parentheses notation that would make the C++ compiler parse the following as a function declaration (rather than as the initialization of an object):

struct Widget { /* ... */ };
struct Gadget { Gadget(Widget const&) { /* ... */ } /* ... */ };

Gadget g(Widget()); // This is parsed a FUNCTION DECLARATION

In the above example, the intent of the programmer may have been to construct an object g of type Gadget and initialize it from a temporary Widget object: however, the compiler would parse this as the declaration of a function called g that returns a Gadget and takes as its argument a (pointer to a) function that accepts no arguments and returns a Widget. This is known as the Most Vexing Parse problem.

Notice, that when using braces the above problem does not exist:

Gadget g{Widget{}}; // This could not be possibly parsed as a function declaration!

(probably too broad, but) Why would the compiler not recognize the curly braces as valid syntax?

That's most likely because you are not using a C++11-compliant compiler. You should be using one, and use the -std=c++11 or -std=c++0x compilation flag to enable C++11 support.