Nested ordered lists

2019-01-15 10:48发布

I need a nested list with subitem numbering, like this:

1. Item 1
  1.1 - Subitem 1
  1.2 - Subitem 2
  1.3 - Subitem 3
  1.4 - Subitem 4
  1.5 - Subitem 5
2. Item 2
  2.1 - Subitem 1
  2.2 - Subitem 2
  2.3 - Subitem 3
  2.4 - Subitem 4
  2.5 - Subitem 5

Well, I know I cannot achieve that with pure HTML. It would be great to use something like this and have the sublist automatically numbered:

<ol>
<li>
   Item 1
   <ol>
     <li>Subitem 1</li>
     <li>Subitem 2</li>
     <li>Subitem 3</li>
     <li>Subitem 4</li>
     <li>Subitem 5</li>
   </ol>
</li>
<li>
   Item 2
   <ol>
     <li>Subitem 1</li>
     <li>Subitem 2</li>
     <li>Subitem 3</li>
     <li>Subitem 4</li>
     <li>Subitem 5</li>
   </ol>
</li>
</ol>

Is there a solution for this using JavaScript or jQuery or something?

3条回答
Rolldiameter
2楼-- · 2019-01-15 11:06

Neither js nor jquery but CSS:

<STYLE type="text/css">
    UL, OL { counter-reset: item }
    LI { display: block }
    LI:before { content: counters(item, "."); counter-increment: item }
</STYLE>

More here: http://www.w3.org/TR/WCAG10-CSS-TECHS/#lists

查看更多
劳资没心,怎么记你
3楼-- · 2019-01-15 11:10

You can use CSS to do so:

OL { counter-reset: item }
LI { display: block }
LI:before { content: counter(item) ". - "; counter-increment: item }
LI LI:before { content: counters(item, ".") " - "; counter-increment: item }

But it requires support for counter and counters.


Edit    Here’s a jQuery approach similar to dcneiner’s but with no limitation to depth:

function foo($ol, counters) {
    counters = counters || [];
    $ol.each(function(i) {
        var $this = $(this);
        $this.children("li").each(function(i) {
            var $this = $(this);
            $this.prepend(counters.concat([i+1]).join(".") + " ");
            $this.children("ol").each(function(j) {
                foo($(this), counters.concat([i+1]));
            });
        });
    });
}
foo($("ol:not(li > ol)"));
查看更多
虎瘦雄心在
4楼-- · 2019-01-15 11:26

If you want to do it cross-browser with jQuery:

$("ol#list ol").each(function(i, el){
   $(this).children().each(function(ci,cel){
      $(this).prepend('<span class="pseudo-num">' + [i + 1, ci + 1].join('.') + ' </span>');
   });
}).addClass('pseudo-processed');

And in your CSS:

ol .pseudo-num { display: none }
ol.pseudo-processed { list-style: none; padding-left: 0 }
ol.pseudo-processed .pseudo-num { display: inline; font-weight: bold }

This is for one level only. You could alter the code to create a recursive function for multiple levels.

This is setup to progressively enhance your page. Without Javascript it would fallback to normal nested numbering.

UPDATE: Thanks to @Gumbo work, I reworked this code into a recursive plugin. It would use the same CSS as in my previous example, but now it is a "full fledged" jQuery plugin with support for any depth:

$.fn.outline = function(options, counters){
    var options  = $.extend({}, $.fn.outline.defaults, options),
        counters = counters || [];

    this.each(function(){
       $(this).children('li').each(function(i){
           var ct = counters.concat([i + 1]);
           if(counters.length){
             $('<span></span>')
                .addClass(options.numberClass)
                .text(ct.join('.') + ' ')
                .prependTo(this);
           }
           $(this).children('ol').outline(options, ct);
       })
    });

    if(!counters.length) this.addClass(options.processedClass)
}

$.fn.outline.defaults = {
       numberClass: 'pseudo-num',
    processedClass: 'pseudo-processed'
}

You could then call it on a specific #id:

 $("#list").outline();

Or use @Gumbo's nice selector to apply it to all ol tags on one page:

 $("ol:not(li > ol)").outline();

And you can either override the defaults globally, or on an individual basis:

 $.fn.outline.defaults.processedClass = 'ol-ready';
 // or
 $("#list").outline({processedClass: 'ol-ready'});
查看更多
登录 后发表回答