Symfony2 internal route in Twig render function

2020-03-26 12:04发布

My layout.html.twig:

{{ render(controller('AcmeDemoBundle:Page:mainmenu')) }}

The Page controller retrieves all pages from the Doctrine and renders mainmenu.html.twig with a set of pages.

My mainmenu.html.twig:

{% if menu_pages is defined %}
    {% for page in menu_pages %}
        <li class="{% if app.request.attributes.get('_internal') == '_page_show' and app.request.get('id') == page.id %}active{% endif %}"><a href="{{ path('_page_show', {id: page.id}) }}">{{ page.title|e }}</a></li>
    {% endfor %}
{% endif %}

But no active class is displayed. As far as I understand the problem is in internal routing. How to fix that?

1条回答
Root(大扎)
2楼-- · 2020-03-26 12:31

Better do not use {{ render(controller('AcmeDemoBundle:Page:mainmenu')) }}. It work more fast and comfortable when you use services instead. You can create a service which will show menu on any page where you include them. And in service you can easy get access to current _route for add active class.

But if you really need to use {{ render(controller('AcmeDemoBundle:Page:mainmenu')) }}, so you need pass to them a current request like:

{{ render(controller('AcmeDemoBundle:Page:mainmenu', {'request': app.request})) }}

and then in action pass request to twig:

public function mainmenuAction($request) {

    return $this->render('AcmeDemoBundle:Page:mainmenu.html.twig', array('request' => $request));
}

and in twig use this request:

{% if menu_pages is defined %}
    {% for page in menu_pages %}
        <li class="{% if request.get('_route') == '_page_show' and request.get('id') == page.id %}active{% endif %}"><a href="{{ path('_page_show', {id: page.id}) }}">{{ page.title|e }}</a></li>
    {% endfor %}
{% endif %}
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