I have a weird math calculation here. I hope someone will explain.
$a = 1.85/100;
$b = 1.5/100;
$c = 1.1/100;
$d = 0.4/100;
$e = 0.4/100;
$f = 0.4/100;
$g = 0.4/100;
$h = $a + $b + $c + $d + $e + $f + $g;
echo $h*100 ."<br>";
$i = $h-$a;
$i = $i-$b;
$i = $i-$c;
$i = $i-$d;
$i = $i-$e;
$i = $i-$f;
$i = $i-$g;
echo $i;
The last $i
value should be 0 but it returns 6.93889390391E-18.
You should read this article:
What Every Computer Scientist Should Know About Floating-Point Arithmetic
Floating point arithmetic is not exact. You should expect small errors. The answer is correct to within a small rounding error. If you need to check if a floating point number is zero it is best not to check that it is exactly equal to zero but instead to check if it is sufficiently close to zero.
If you really need exact arithmetic, don't use floating point types. In your example you could multiply all your numbers by 100 and use integer arithmetic to get an exact answer.
Yeah,
round($i, 2)
The "discrepancies" are usually so small, that rounding it to 2 decimals will almost always solve the problem.
There is nothing wrong going there, there are simply rounding approximation.
In this very cas you should multiply all your values for 1000 and do a division at the end of the calculation or, better, resort to precise calculation extension