Update 1:
Because my question is not clear, so I post second example
Because row 2, there is value 1 at Item 04 so the Get Item Name = Item 04. It is random and have a large number of columns (500).
The problem:
I would like to have a way to get a column header if there is any value input to the cells under that header. Please note that if at row 2 and column 1 has value, then other cell of row 2 will not have any value (other than 0).
It is hard to explain the problem in words so I have created an example.
I posted a formula in the comments above, you may not have seen it. This is it:
=IF(COUNTA($B2:$D2)=0,"",INDEX($B$1:$D$1,MATCH(TRUE,INDEX($B2:$D2<>"",0),0)))
that will get the header for the first instance of a populated cell - if you have numeric values and want to ignore zeroes change to
=IF(COUNTA($B2:$D2)=0,"",INDEX($B$1:$D$1,MATCH(TRUE,INDEX($B2:$D2>0,0),0)))
Either way the formula can be extended to as large a range as you need
.....and if you have 500 columns you could use IFERROR to shorten a little
=IFERROR(INDEX($B$1:$D$1,MATCH(TRUE,INDEX($B2:$D2>0,0),0)),"")
I assume that when you say "column header" you really mean "row header".
Considering that the first cell (containing the text
"Column Header"
) is atA1
this is the formula you have to introduce in cellA2
:Drag this formula down on as many rows as you need and it'll (hopefully) achieve what you want.
Assuming that you want a solution with more than 3 columns, this formula will return you the right header.
I assume that you data starts in row 2, column B - and row 1 contains the column headers.
Use this formula in B1 and copy it down:
If your data extends further than column D, simply change this in the formula.
for a particular table which is relative small table with countable number of columns (i.e 3) try this
my question is what if you have table contain 20 or 100 columns?