Add a Timeout for getchar()

2020-03-18 07:10发布

I need to add a timeout function for getchar() in my program.

What do I do so that when my program reaches the instruction getchar(), it will only wait for a certain amount of time for the user to make a keystroke and if the user does not make a keystroke within the given time limit, the program will "skip" the getchar()?

The operating system does not support the conio.h library so kbhit is not an option.

2条回答
Explosion°爆炸
2楼-- · 2020-03-18 07:25

How to add a timeout when reading from `stdin` I found this question is helpful.

Another method is using multithreading.

If you are using c++11, you can make use of condition_variable::wait_for() as a timer thread. And the original getchar() is blocking on another thread.

Here is an example:

#include <termios.h>
#include <unistd.h>
#include <thread>
#include <chrono>
#include <iostream>

std::mutex mtx;
std::condition_variable cv;

int ch;
bool INPUT_SIGNAL = false;

void getch ( void ) {
  struct termios oldt, newt;

  tcgetattr ( STDIN_FILENO, &oldt );
  newt = oldt;
  newt.c_lflag &= ~( ICANON | ECHO );

  tcsetattr ( STDIN_FILENO, TCSANOW, &newt );
  ch = getchar();
  tcsetattr ( STDIN_FILENO, TCSANOW, &oldt );

  INPUT_SIGNAL = true;  

  cv.notify_one();
}

void timer ( int period ) {
    for(;;) {
        std::unique_lock<std::mutex> lck(mtx);

        cv.wait_for(lck, std::chrono::seconds(period), []{return INPUT_SIGNAL;});   

        if(INPUT_SIGNAL) {
            INPUT_SIGNAL = false;
            std::cout << ch << "\n";
        } else {
            std::cout << 0 << "\n";
        }
    }
}

int main() {
    std::thread worker(timer, 1);
    for(;;) {
        getch();
    }
    worker.join();
    return 0;
}

When there is a keystroke, main thread will notify the worker thread.

查看更多
虎瘦雄心在
3楼-- · 2020-03-18 07:27

This is usually achieved by using select() on stdin. Another solution would be using alarm() and a dummy SIGALRM handler to interrupt the getchar() call (only working on POSIX systems though).

查看更多
登录 后发表回答