why doesn't this code throw NullPointerExcepti

2020-03-10 04:56发布

I was just discussing about calling static methods using class name with my friend and tried out this code and expected it to throw NPE at runtime.but as it turn out it dint. i just want to understand the execution order.

public class One {

    public static void method() {
        System.out.println("in static one");
    }
}

public class Two {

    static One o;

    public static void main(String[] args) {
        o.method(); // expected NPE here, as o is null
    }
}

I know that static methods should be invoked with their class name, I even know that IDE's would give a compiler warning when we call static methods with an instance. but we could also call them by creating an instance, however, i never created an instance here, o should get its default value null, thus calling o.method() should throw an NPE at run time, but it doesn't. can you guys please shed some light on how the execution order is in this code.

5条回答
我想做一个坏孩纸
2楼-- · 2020-03-10 05:40

Because you declare static One o; outside the main function. You can try to declare it inside the main function, it cannot even be compiled...

Or you can declare it as One o = null in main, then it will be compiled but it's the same as One.method()

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走好不送
3楼-- · 2020-03-10 05:43

If you would have opened the code in your Development Environment e.g (Eclipse), instead of fooling people by showing the code here, which does provide code formating for static methods in italic style, then you would have seen that checkstyle claims about "Do not call a static method on an instance".

So it should be

One.method()

instead of

o.method()

Then it is clear why it does not crash!

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SAY GOODBYE
4楼-- · 2020-03-10 05:47

method is static so it doesn't care about the One instance.

One o = null;
o.method();

Is the same as:

One.method();
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等我变得足够好
5楼-- · 2020-03-10 06:00

It works because what matters is the compile-time type of the o field. The compiler will compile o.method() into the same byte code as One.method().

In particular, if you had a class Two that extends One, and both declare a static void method(), then

One x = new Two();
x.method(); // calls One.method(), not Two.method()

Good for obfuscation purposes, less good for maintainability...

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趁早两清
6楼-- · 2020-03-10 06:03

static methods or variables are associated with class definition itself and not with the class instance. Hence your method() is available on o, but Ideally you should call it using the class name itself as:

     One.method();//static way of calling static methods
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