Object Required Error in excel VBA [duplicate]

Question

This question already has answers here:

What is the difference between dim and set in vba (7 answers)

Closed 6 years ago.

Dim g1val, g2val As Integer

Set g1val = 0
Set g2val = 0

For i = 3 To 18
    If g1val > Cells(33, i).Value Then
        g1val = g1val
    Else
        g1val = Cells(33, i).Value
    End If
Next i

For j = 32 To 57
    If g2val > Cells(31, j).Value Then
        g2val = g2val
    Else
        g2val = Cells(31, j).Value
    End If
Next j

Here on second line i am getting an error saying object required.I have tried to make g1val and g2val as "Double" and tried to give 1 for their values at first.But those didn't work out. Can u help??....

Answer 1

The Set statement is only used for object variables (like Range, Cell or Worksheet in Excel), while the simple equal sign '=' is used for elementary datatypes like Integer. You can find a good explanation for when to use set here.

The other problem is, that your variable g1val isn't actually declared as Integer, but has the type Variant. This is because the Dim statement doesn't work the way you would expect it, here (see example below). The variable has to be followed by its type right away, otherwise its type will default to Variant. You can only shorten your Dim statement this way:

Dim intColumn As Integer, intRow As Integer  'This creates two integers

For this reason, you will see the "Empty" instead of the expected "0" in the Watches window.

Try this example to understand the difference:

Sub Dimming()

  Dim thisBecomesVariant, thisIsAnInteger As Integer
  Dim integerOne As Integer, integerTwo As Integer

  MsgBox TypeName(thisBecomesVariant)  'Will display "Empty"
  MsgBox TypeName(thisIsAnInteger )  'Will display "Integer"
  MsgBox TypeName(integerOne )  'Will display "Integer"
  MsgBox TypeName(integerTwo )  'Will display "Integer"

  'By assigning an Integer value to a Variant it becomes Integer, too
  thisBecomesVariant = 0
  MsgBox TypeName(thisBecomesVariant)  'Will display "Integer"

End Sub

---

Two further notices on your code:

First remark: Instead of writing

'If g1val is bigger than the value in the current cell
If g1val > Cells(33, i).Value Then
  g1val = g1val   'Don't change g1val
Else
  g1val = Cells(33, i).Value  'Otherwise set g1val to the cell's value
End If

you could simply write

'If g1val is smaller or equal than the value in the current cell
If g1val <= Cells(33, i).Value Then
  g1val = Cells(33, i).Value  'Set g1val to the cell's value 
End If

Since you don't want to change g1val in the other case.

Second remark: I encourage you to use Option Explicit when programming, to prevent typos in your program. You will then have to declare all variables and the compiler will give you a warning if a variable is unknown.

Answer 2

In order to set the value of integer variable we simply assign the value to it. eg g1val = 0 where as set keyword is used to assign value to object.

Sub test()

Dim g1val, g2val As Integer

  g1val = 0
  g2val = 0

    For i = 3 To 18

     If g1val > Cells(33, i).Value Then
        g1val = g1val
    Else
       g1val = Cells(33, i).Value
     End If

    Next i

    For j = 32 To 57
        If g2val > Cells(31, j).Value Then
           g2val = g2val
        Else
          g2val = Cells(31, j).Value
        End If
    Next j

End Sub