Lets say I have the following xml (a quick example)
<rows>
<row>
<name>one</name>
</row>
<row>
<name>two</name>
</row>
</rows>
I am trying to parse this by using XmlDocument and XPath (ultimately so I can make a list of rows).
For example...
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
foreach(XmlNode row in doc.SelectNodes("//row"))
{
string rowName = row.SelectSingleNode("//name").InnerText;
}
Why, within my foreach loop, is rowName always "one"? I am expecting it to be "one" on the first iteration and "two" on the second.
It seems that //name gets the first instance in the document, rather than the first instance in the row as I would expect. After all, I am calling the method on the "row" node. If this is "just how it works" then can anybody please explain how I could change it to work to my needs?
Thank you
Use the following
Is the code you posted actually correct? I get a compile error on row.SelectNode() as it isn't a member of XmlNode.
Anyway, my example above works, but assumes only a single
<name>
node within the<row>
node so you may need to useSelectNodes()
instead ofSelectSingleNode()
if that is not the case.As others have shown, use
.InnerText
to get just the value.Your second xpath starts with
//
. This is an abbreviation for/descendant-or-self::node()
, which you can see starts with/
, meaning it searches from the root of the document, whatever the context in which you use it.You probably want one of:
to find the
name
nodes that are immediate children of therow
, orto find
name
nodes *anywhere underthe
row. Note the
.` in this second xpath that causes the xpath to start from the context node.Use a relative path e.g.
string rowName = row.SelectSingleNode("name").InnerText;
.The problem is in your second XPath query:
This has a global scope, so no matter where you call it from, it will select all
row
elements.It should work if you replace your expression with:
Use LINQ to XML. Include
using System.Xml.Linq;
in your code file and then do the following code to get your listThat will give you a list of the name elements. Then if you want to turn that into a
List<string>
just do this: