I need to copy from input document to output document all attributes but one.
My input is like this:
<mylink id="nextButton" type="next" href="javascript:;" />
And I need output like this:
<a id="nextButton" href="javascript:;" />
If I use the following XSL:
<xsl:template match="mylink">
<a><xsl:copy-of select="attribute::*"/></a>
</xsl:template>
I get all attributes to output like this:
<a id="nextButton" type="next" href="javascript:;" />
But I want to ignore the "type" attribute. I've tried the following but none of them seems to work the way I need:
<xsl:copy-of select="attribute::!type"/>
<xsl:copy-of select="attribute::!'type'"/>
<xsl:copy-of select="attribute::*[!type]"/>
<xsl:copy-of select="attribute::not(type)"/>
How should I write my stylesheet to get needed output?
In XSLT 2.0:
Shortest form:
Longer one (that's the first thing I came up with, I leave it for reference):