import subprocess
retcode = subprocess.call(["/home/myuser/go.sh", "abc.txt", "xyz.txt"])
When I run these 2 lines, will I be doing exactly this?:
/home/myuser/go.sh abc.txt xyz.txt
Why do I get this error? But when I run go.sh normally, I don't get that error.
File "/usr/lib/python2.6/subprocess.py", line 480, in call
return Popen(*popenargs, **kwargs).wait()
File "/usr/lib/python2.6/subprocess.py", line 633, in __init__
errread, errwrite)
File "/usr/lib/python2.6/subprocess.py", line 1139, in _execute_child
raise child_exception
OSError: [Errno 8] Exec format error
I just got this error on Mac OS, while trying to call a one-line script using
subprocess.call
. The script ran fine when called from the command line. After adding the shebang line#!/usr/bin/env sh
, it also ran fine viasubprocess.call
.It appears, while the shell has a default executor for text files marked executable,
subprocess.Popen
does not.