Django - Display ImageField

Question

i just start to use django and i haven't found a lot of info on how to display an imageField, so i made this:

models.py

class Car(models.Model):
    name = models.CharField(max_length=255)
    price = models.DecimalField(max_digits=5, decimal_places=2)
    photo = models.ImageField(upload_to='site_media')

views.py

def image(request):
    carx = Car()
    variables = RequestContext(request,{
        'carx':carx
    })
    return render_to_response('image.html',variables)

image.html

{% extends "base.html" %}
{% block content %}
   <img src=carx />
{% endblock %}

I already save an image since terminal and i know is there, also if a do this in image.html:

{% block content %}
    {{ carx }}
{% endblock %}

The ouput is: Car object

Can anyone tell me where is my error?

Thanks a lot.

Answer 1

Thanks to all, i fix it in this way.

views.py

def image(request):
carx = Car.objects.all()
for mycar in carx:
    MyCar = mycar.photo.url
variables = RequestContext(request,{
    'carx':MyCar
})
return render_to_response('image.html',variables)

image.html

{% extends "base.html" %}

{% block content %}
     <img src="{{ MEDIA_URL }}{{ carx }}"/>
{% endblock %}

settings.py

 MEDIA_URL = '/Users/gcarranza/PycharmProjects/django_bookmarks/'
 STATIC_URL = '/Users/gcarranza/PycharmProjects/django_bookmarks/site_media/'
 STATICFILES_DIRS = (
 '/Users/gcarranza/PycharmProjects/django_bookmarks/site_media',)

Now i know that carx.photo.url retrieve the absolute path of the file and its only matter to load as static file.

Answer 2

An ImageField contains a url attribute, which you can use in your templates to render the proper HTML.

{% block content %}
    <img src="{{ carx.photo.url }}">
{% endblock %}

Answer 3

You can also make use of the Static URL in Settings.py. Make a directory for example "Uploads", in the Static directory of your app. Also change this in your model in models.py.

Use the following code:

<img src="{% static carx.photo.url %}" />