Python for loop start counter initialization

Question

for iteration in range(len(list) - 1):
  index = iteration +1 #This is the line which has no effect on the inner loop
  for index in range(len(list)):
    if list[iteration] > list[index]:
      newmin  = list[index]
      newminindex = index        
  if iteration != newminindex :
    swapnumbers(list,iteration, newminindex)

The above is a code snippet I wrote for selection sort algorithm. However I see the inner loop start counter always starting from 0. Request for expert comment.

Answer 1

for index in range(iteration + 1, len(list))

Answer 2

You really should be using enumerate for stuff like this, as you can loop through the index and the value at the same time (which will save you the hassle of using two for-loops).

for i, j in enumerate(list):
    print i, j

Your inner loop is overriding the variable index that you defined in the first loop.

Answer 3

The for index in range(len(list)) loop executes the loop body with index first set to 0, then 1, then 2, etc. up to len(list) - 1. The previous value of index is ignored and overwritten. If you want index to start at iteration + 1, use the 2-argument form of range:

for index in range(iteration + 1, len(list)):

Answer 4

Try this instead:

for index in range(iteration + 1, len(l)):  # don't use "list" as a name

index is being reassigned anyway within the for-loop so index = iteration + 1 is not having any effect.