Whenever I need to reference a common module or script, I like to use paths relative to the current script file, that way, my script can always find other scripts in the library.
So, what is the best, standard way of determining the directory of the current script? Currently, I'm doing:
$MyDir = [System.IO.Path]::GetDirectoryName($myInvocation.MyCommand.Definition)
I know in modules (.psm1) you can use $PSScriptRoot
to get this information, but that doesn't get set in regular scripts (i.e. .ps1 files).
What's the canonical way to get the current PowerShell script file's location?
If you are creating a V2 Module, you can use an automatic variable called
$PSScriptRoot
.From PS > Help automatic_variable
PowerShell 3+
PowerShell 2
Prior to PowerShell 3, there was not a better way than querying the
MyInvocation.MyCommand.Definition
property for general scripts. I had the following line at the top of essentially every powershell script I had:Maybe i'm missing something here... but if you want the present working directory you can just use this:
(Get-Location).Path
for a string, orGet-Location
for an object.Unless you're referring to something like this, which I understand after reading the question again.
I needed to know the script name and where it is executing from.
Prefixing "$global:" to the MyInvocation structure returns the full path and script name when called from both the main script, and the main line of an imported .PSM1 library file. It also works from within a function in an imported library.
After much fiddling around, I settled on using $global:MyInvocation.InvocationName. It works reliably with CMD launch, Run With Powershell, and the ISE. Both local and UNC launches return the correct path.
For Powershell 3+
I've placed this function in my profile. Works in ISE using F8/Run Selection too.