Determining age of a file in shell script

Question

G'day,

I need to see if a specific file is more than 58 minutes old from a sh shell script. I'm talking straight vanilla Solaris shell with some POSIX extensions it seems.

I've thought of doing a

touch -t YYYYMMDDHHmm.SS /var/tmp/toto

where the timestamp is 58 minutes ago and then doing a

find ./logs_dir \! -newer /var/tmp/toto -print

We need to postprocess some log files that have been retrieved from various servers using mirror. Waiting for the files to be stable is the way this team decides if the mirror is finished and hence that day's logs are now complete and ready for processing.

Any suggestions gratefully received.

cheers,

Answer 1

A piece of the puzzle might be using stat. You can pass -r or -s to get a parseable representation of all file metadata.

find . -print -exec stat -r '{}' \;

AFAICR, the 10th column will show the mtime.

Answer 2

I needed something to test age of a specific file, to not re-download too often. So using GNU date and bash:

# if file's modtime hour is less than current hour:
[[ $(date +%k -r GPW/mstall.zip) -lt $(date +%k) ]] && \
wget -S -N \
http://bossa.pl/pub/metastock/mstock/mstall.zip \

Update--this version works much better for me, and is more accurate and understandable:

[[ $(date +%s -r mstall.zip) -lt $(date +%s --date="77 min ago") ]] && echo File is older than 1hr 17min

The BSD variant (tested on a Mac) is:

[[ $(stat -f "%m" mstall.zip) -lt $(date -j -v-77M +%s) ]] && echo File is older than 1hr 17min

Answer 3

Since you're looking to test the time of a specific file you can start by using test and comparing it to your specially created file:

test /path/to/file -nt /var/tmp/toto

or:

touch -t YYYYMMDDHHmm.SS /var/tmp/toto
if [/path/to/file -nt /var/tmp/toto]
   ...

Answer 4

This is now an old question, sorry, but for the sake of others searching for a good solution as I was...

The best method I can think of is to use the find(1) command which is the only Un*x command I know of that can directly test file age:

if [ "$(find $file -mmin +58)" != "" ]
then
  ... regenerate the file ...
fi

The other option is to use the stat(1) command to return the age of the file in seconds and the date command to return the time now in seconds. Combined with the bash shell math operator working out the age of the file becomes quite easy:

age=$(stat -c %Y $file)
now=$(date +"%s")
if (( (now - age) > (58 * 60) ))
then
    ... regenerate the file ...
fi

You could do the above without the two variables, but they make things clearer, as does use of bash math (which could also be replaced). I've used the find(1) method quite extensively in scripts over the years and recommend it unless you actually need to know age in seconds.

Answer 5

You can use ls and awk to get what you need as well. Awk has a c-ish printf that will allow you to format the columns any way you want.

I tested this in bash on linux and ksh on solaris.

Fiddle with options to get the best values for your application. Especially "--full-time" in bash and "-E" in ksh.

bash

ls -l foo | awk '{printf "%3s %1s\n", $6, $7}'

2011-04-19 11:37

ls --full-time foo | awk '{printf "%3s %1s\n", $6, $7}'

2011-04-19 11:37:51.211982332

ksh

ls -l bar | awk '{printf "%3s %1s %s\n", $6, $7, $8}'

May 3 11:19

ls -E bar | awk '{printf "%3s %1s %s\n", $6, $7, $8}'

2011-05-03 11:19:23.723044000 -0400

Answer 6

You can use different units in the find command, for example:

find . -mtime +0h55m

Will return any files with modified dates older than 55 minutes ago.