Is C# 4.0 Tuple covariant

2020-03-01 09:45发布

(I would check this out for myself, but I don't have VS2010 (yet))

Say I have 2 base interfaces:

IBaseModelInterface
IBaseViewInterface

And 2 interfaces realizing those:

ISubModelInterface : IBaseModelInterface
ISubViewInterface : IBaseViewInterface

If I define a Tuple<IBaseModelInterface, IBaseViewInterface> I would like to set that based on the result of a factory that returns Tuple<ISubModelInterface, ISubViewInterface>.

In C# 3 I can't do this even though the sub interfaces realize the base interfaces. And I'm pretty sure C# 4 lets me do this if I was using IEnumerable<IBaseModelInterface> because it's now defined with the in keyword to allow covariance. So does Tuple allow me to do this?

From what (little) I understand, covariance is only allowed on interfaces, so does that mean there needs to be an ITuple<T1, T2> interface? Does this exist?

2条回答
乱世女痞
2楼-- · 2020-03-01 09:55

You can inherit from tuple for create your own Covariant Tuple. This way you avoid to have to rewrite your own equalities logic.

public interface ICovariantTuple<out T1>
{
    T1 Item1 { get; }
}
public class CovariantTuple<T1> : Tuple<T1>, ICovariantTuple<T1>
{
    public CovariantTuple(T1 item1) : base(item1) { }
}

public interface ICovariantTuple<out T1, out T2>
{
    T1 Item1 { get; }
    T2 Item2 { get; }
}
public class CovariantTuple<T1, T2> : Tuple<T1, T2>, ICovariantTuple<T1, T2>
{
    public CovariantTuple(T1 item1, T2 item2) : base(item1, item2) { }
}

etc.... for 3, 4, 5, 6, 7, 8 items

Compile Fail

Tuple<Exception> item = new Tuple<ArgumentNullException>(null);

Compile Success

ICovariantTuple<Exception> item = new CovariantTuple<ArgumentNullException>(null);

There is no base Tuple after 8 items, but it should be enough.

查看更多
做自己的国王
3楼-- · 2020-03-01 09:58

Tuple is a class (well, a family of classes) - it's invariant by definition. As you mention later on, only interfaces and delegate types support generic variance in .NET 4.

There's no ITuple interface that I'm aware of. There could be one which would be covariant, as the tuples are immutable so you only get values "out" of the API.

查看更多
登录 后发表回答