Get object keys with the highest value in Javascri

Question

Imagine an object like this:

var values = {
    "2": 1,
    "53": 2,
    "56": 4,
    "57": 9,
    "61": 2,
    "62": 16,
    "63": 2,
    "398": 24,
    ...
}

My goal is, to find the 10 object keys, which have the highest value. In this case: 398, then 62 and so on (= [398, 62, ...]). I know how I can put this into an array, don't know how to receive the property key though.

Important: I can't change the format because it's a server response.

I tried with a for (key in values) {} loop but have no idea how to move on. This similar question and it's answer couldn't really help me either.

Answer 1

var value = {
    "2": 1,
    "53": 2,
    "56": 4,
    "57": 9,
    "61": 2,
    "62": 16,
    "63": 2,
    "398": 24
};

var sortable = [];
for (var key in value) {
    sortable.push([key, value[key]]);
}

sortable.sort(function(a, b) {
    return b[1] - a[1];
});

var result = [];
sortable.forEach(function(a) {
  result.push(a[0]);
});

console.log(result.slice(0, 10));

Answer 2

As commented before:

• Create an array of keys: Object.keys(object)
• Sort this array based on value: sort((a,b)=> object[b] - object[a])
• Get necessary values: keys.slice(0,n)

var value = {2:1,53:2,56:4,57:9,61:2,62:16,63:2,398:24};

function getKeysWithHighestValue(o, n){
  var keys = Object.keys(o);
  keys.sort(function(a,b){
    return o[b] - o[a];
  })
  console.log(keys);
  return keys.slice(0,n);
}

console.log(getKeysWithHighestValue(value, 4))

Answer 3

You could sort by the values property and slice the result.

var values = { 2: 1, 53: 2, 56: 4, 57: 9, 61: 2, 62: 16, 63: 2, 398: 24 },
    result = Object
        .keys(values)
        .sort(function (a, b) { return values[b] - values[a]; })
        .slice(0, 10)
        .map(Number);

console.log(result);

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Answer 4

You can use Object.keys to get key values

var value = {
"2": 1,
"53": 2,
"56": 4,
"57": 9,
"61": 2,
"62": 16,
"63": 2,
"398": 24,
}
var parsedKeys = Object.keys(value).map(x => parseInt(x));
var sortedKeys = parsedKeys.sort(function (a, b) {  return b - a;  });

Now you can get highest top 10 keys by sortedKeys.slice(0, 10);