I am trying to click on the first result on the google result. Here is my code where I am entering chennai craiglist which is read from csv file. So I am sure the first link that come in the organic result will be chennai.craiglist.org. But I am quiet not sure about how to do this.
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import Select
from selenium.common.exceptions import NoSuchElementException
import unittest, time, re
class Browse(unittest.TestCase):
def setUp(self):
self.driver = webdriver.Firefox()
self.driver.implicitly_wait(30)
self.base_url = "http://google.com/"
filename = 'test.csv'
line_number = 1
with open(filename, 'rb') as f:
mycsv = csv.reader(f)
mycsv = list(mycsv)
self.cityname=mycsv[line_number][0]
self.username=mycsv[line_number][1]
self.password=mycsv[line_number][2]
self.verificationErrors = []
def test_browse(self):
driver = self.driver
driver.get(self.base_url + "/")
driver.find_element_by_id("gbqfq").send_keys(self.cityname)
I wanna know what should come after this line?
UPDATE
right now I am giving like
driver.find_elements_by_xpath(".//*[@id='rso']//div//h3/a")[:1].click()
I am not sure if it will work or not.
The
xpath
you have chosen is 'ok' but probably not the best.I've been using
driver.find_element_by_tag_name("cite").click()
in python3 which has worked for me. However if you just want the link to the top search result it would be faster to use the requests and BeautifulSoup libraries as shown belowThis works great with google results.