How to click on the first result on google using s

2020-02-29 10:09发布

I am trying to click on the first result on the google result. Here is my code where I am entering chennai craiglist which is read from csv file. So I am sure the first link that come in the organic result will be chennai.craiglist.org. But I am quiet not sure about how to do this.

from selenium import webdriver
    from selenium.webdriver.common.by import By
    from selenium.webdriver.support.ui import Select
    from selenium.common.exceptions import NoSuchElementException
    import unittest, time, re

    class Browse(unittest.TestCase):
    def setUp(self):
    self.driver = webdriver.Firefox()
    self.driver.implicitly_wait(30)
    self.base_url = "http://google.com/"

    filename = 'test.csv'
    line_number = 1
    with open(filename, 'rb') as f:
        mycsv = csv.reader(f)
        mycsv = list(mycsv)
        self.cityname=mycsv[line_number][0]
        self.username=mycsv[line_number][1]
        self.password=mycsv[line_number][2]
        self.verificationErrors = []

def test_browse(self):
    driver = self.driver
    driver.get(self.base_url + "/")
    driver.find_element_by_id("gbqfq").send_keys(self.cityname)

I wanna know what should come after this line?

UPDATE

right now I am giving like

driver.find_elements_by_xpath(".//*[@id='rso']//div//h3/a")[:1].click()

I am not sure if it will work or not.

3条回答
混吃等死
2楼-- · 2020-02-29 10:43

The xpath you have chosen is 'ok' but probably not the best.

result = driver.find_elements_by_xpath("//ol[@id="rso"]/li")[0] //make a list of results and get the first one
result.find_element_by_xpath("./div/h3/a").click() //click its href
查看更多
▲ chillily
3楼-- · 2020-02-29 10:44

I've been using driver.find_element_by_tag_name("cite").click() in python3 which has worked for me. However if you just want the link to the top search result it would be faster to use the requests and BeautifulSoup libraries as shown below

#!/usr/bin/env python3
import requests
from bs4 import BeautifulSoup
url = 'http://www.google.com/search?q=something'
page = requests.get(url)
soup = BeautifulSoup(page.text, "html.parser")
print(soup.find('cite').text)
查看更多
等我变得足够好
4楼-- · 2020-02-29 10:47

This works great with google results.

results = driver.find_elements_by_xpath('//div[@class="r"]/a/h3')  # finds webresults
results[0].click(). # clicks the first one
查看更多
登录 后发表回答