Returning From a Void Function in C++

Question

Consider the following snippet:

void Foo()
{
  // ...
}

void Bar()
{
  return Foo();
}

What is a legitimate reason to use the above in C++ as opposed to the more common approach:

void Foo()
{
  // ...
}

void Bar()
{
  Foo();

  // no more expressions -- i.e., implicit return here
}

Answer 1

Could be a case where Foo() originally returned a value, but was later changed to void, and the person who updated it just didn't think very clearly.