Hi I'm trying to interpolate a Dataframe where I have a datetimeIndex index.
Here's the data
res = pd.DataFrame(cursor.execute("SELECT DATETIME,VALUE FROM {} WHERE DATETIME > ? AND DATETIME < ?".format(table),[start,end]).fetchall(),columns=['date','value'])
res.set_index('date',inplace=True)
which produces
2013-01-31 00:00:00 517
2012-12-31 00:00:00 263
2012-11-30 00:00:00 1917
2012-10-31 00:00:00 391
2012-09-30 00:00:00 782
2012-08-31 00:00:00 700
2012-07-31 00:00:00 799
2012-06-30 00:00:00 914
2012-05-31 00:00:00 141
2012-04-30 00:00:00 342
2012-03-31 00:00:00 199
2012-02-29 00:00:00 533
2012-01-31 00:00:00 1393
2011-12-31 00:00:00 497
2011-11-30 00:00:00 1457
2011-10-31 00:00:00 997
2011-09-30 00:00:00 533
2011-08-31 00:00:00 626
2011-07-31 00:00:00 1933
2011-06-30 00:00:00 4248
2011-05-31 00:00:00 1248
2011-04-30 00:00:00 904
2011-03-31 00:00:00 3280
2011-02-28 00:00:00 390
2011-01-31 00:00:00 601
2010-12-31 00:00:00 423
2010-11-30 00:00:00 748
2010-10-31 00:00:00 433
2010-09-30 00:00:00 734
2010-08-31 00:00:00 845
2010-07-31 00:00:00 1693
2010-06-30 00:00:00 2742
2010-05-31 00:00:00 669
This is all non contiguous. I want to have a daily value so, want to fill in the missing values using some kind of interpolation.
First tried to set the index and then interpolate.
new_index = pd.date_range(date(2010,1,1),date(2014,1,31),freq='D')
df2 = res.reindex(new_index) # This returns NaN
df2.interpolate('cubic') # Fails with error TypeError: Cannot interpolate with all NaNs.
What I would hope to get back is a dataframe with each date value between 2010-2014, with a interpolated value calculated from the points surrounding it.
It seems like there probably is a way to do this simply, but I'm not sure what.
Here's one way to do it.
First get a new index from
max min
ofdf.index
datesThen use
interpolate(method='linear')
on the series to get values.Just as an add on to @JohnGalt's answer, you could also use
resample
which is slightly more convenient thanreindex
here: