How to pass List from Controller to View in MVC 3

2020-02-23 05:50发布

I have a List<> binded with some data in Controller action and I want to pass that List<> to View to bind with DataGrid in Razor View.

I am new to MVC.Can any one help me how to pass and how to access in View.

4条回答
迷人小祖宗
2楼-- · 2020-02-23 05:55
  1. Create a model which contains your list and other things you need for the view.

    For example:

    public class MyModel
    {
        public List<string> _MyList { get; set; }
    }
    
  2. From the action method put your desired list to the Model, _MyList property, like:

    public ActionResult ArticleList(MyModel model)
    {
        model._MyList = new List<string>{"item1","item2","item3"};
        return PartialView(@"~/Views/Home/MyView.cshtml", model);
    }
    
  3. In your view access the model as follows

    @model MyModel
    foreach (var item in Model)
    {
       <div>@item</div>
    }
    

I think it will help for start.

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一纸荒年 Trace。
3楼-- · 2020-02-23 05:59

I did this;

In controller:

public ActionResult Index()
{
  var invoices = db.Invoices;

  var categories = db.Categories.ToList();
  ViewData["MyData"] = categories; // Send this list to the view

  return View(invoices.ToList());
}

In view:

@model IEnumerable<abc.Models.Invoice>

@{
    ViewBag.Title = "Invoices";
}

@{
  var categories = (List<Category>) ViewData["MyData"]; // Cast the list
}

@foreach (var c in @categories) // Print the list
{
  @Html.Label(c.Name);
}

<table>
    ...
    @foreach (var item in Model) 
    {
      ...
    }
</table>

Hope it helps

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戒情不戒烟
4楼-- · 2020-02-23 06:06

You can use the dynamic object ViewBag to pass data from Controllers to Views.

Add the following to your controller:

ViewBag.MyList = myList;

Then you can acces it from your view:

@ViewBag.MyList

// e.g.
@foreach (var item in ViewBag.MyList) { ... }
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孤傲高冷的网名
5楼-- · 2020-02-23 06:09

Passing data to view is simple as passing object to method. Take a look at Controller.View Method

protected internal ViewResult View(
    Object model
)

Something like this

//controller

List<MyObject> list = new List<MyObject>();

return View(list);


//view

@model List<MyObject>

// and property Model is type of List<MyObject>

@foreach(var item in Model)
{
    <span>@item.Name</span>
}
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