List file using ls command in Linux with full path

Question

Many will found that this is repeating questions but i have gone through all the questions before asked about this topic but none worked for me.

I want to print full path name of the certain file format using ls command so far i found chunk of code that will print all the files in the directory but not full path.

for i in io.popen("ls /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7"):lines() do
  if string.find(i,"%.*$") then 
     print(i) 
  end
end

this will print out all the file in root diractory and subdiratory.

Output:

  0020111118223425.lvf
  2012
  2012 (2009).mp4
  3 Idiots
  Aashiqui 2
  Agneepath.mkv
  Avatar (2009)
  Captain Phillips (2013)
  Cocktail

I want output like:

  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/0020111118223425.lvf           [File in Root Directory]
  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/2012/2012.mkv
  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/2012 (2009).mp4                [File in Root Directory]
  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/3 Idiots/3 Idiots.mkv
  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/Aashiqui 2/Aashiqui 2.mkv
  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/Avatar (2009)/Avatar (2009).mkv
  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/Captain Phillips (2013).mkv
  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/Cocktail/Cocktail.mkv

EDIT: I have used this all but its not working with my code in LUA.

when I used with my code it displays wrong directory

for i in io.popen("ls -d $PWD/* /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7"):lines() do
    if string.find(i,"%.*$") then
      print("/mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/"..i)
    end
  end

is not finding files in "/mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7" insted its prints the machines root directory files.

Answer 1

You can try this:

ls -d $PWD/*

Answer 2

you just want the full path why not use the utility meant for that a combination of readlink and grep should get you what you want

grep -R  '--include=*.'{mkv,mp4} ? | cut -d ' ' -f3  | xargs readlink -e # 
the question mark should be replaced with the right pattern - this is almost right
# this is probably the best solution remove the grep part if you dont need a filter
find <dirname> | grep .mkv | xargs readlink -e |  xargs ls --color=auto # only matroska files in the dir and subdirs with nice color - also you can edit ls flags
find /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7 | grep .mkv 
find /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7 | xargs grep -R  '--include=*.'{mkv,mp4} . | cut -d ' ' -f3 # I am sure you can do more with grep 
readlink -f `ls` # in the directory or 

Answer 3

This prints all files, recursively, from the current directory.

find "$PWD" | awk /.ogg/ # filter .ogg files by regex
find "$PWD" | grep .ogg  # filter .ogg files by term
find "$PWD" | ack .ogg   # filter .ogg files by regex/term using https://github.com/petdance/ack2

Answer 4

The ls command will only print the name of the file in the directory. Why not do something like

print("/mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/" + i)

This will print out the directory with the filename.

Answer 5

You can use

  ls -lrt -d -1 "$PWD"/{*,.*}   

It will also catch hidden files.

Answer 6

There is more than one way to do that, the easiest I think would be:

find /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7

also this should work:

(cd /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7; ls | xargs -i echo `pwd`/{})