How to send an image from a telegram bot

2020-02-16 04:56发布

I have my bot working by now, but the thing is it can only send text. I have seen in the Bot API there are functions to send photos, videos... but I can't get it to work. Someone has achieved it? I'm using python source code from yukuku/telebot

 elif text == '/image':
            img = Image.new('RGB', (512, 512))
            base = random.randint(0, 16777216)
            pixels = [base+i*j for i in range(512) for j in range(512)]  # generate sample image
            img.putdata(pixels)
            output = StringIO.StringIO()
            img.save(output, 'JPEG')
            reply(img=output.getvalue())

When I change the code, nothing happened.

img = Image.open('image.png')
img.show()

Please help me. I need the correct code. Sorry for my bad English.

4条回答
走好不送
2楼-- · 2020-02-16 05:18

I have included two functions, one is good for sending local images, the other one is good for sending remote images.

def sendImage():
    url = "https://api.telegram.org/bot<Token>/sendPhoto";
    files = {'photo': open('/path/to/img.jpg', 'rb')}
    data = {'chat_id' : "YOUR_CHAT_ID"}
    r= requests.post(url, files=files, data=data)
    print(r.status_code, r.reason, r.content)

def sendImageRemoteFile(img_url):
    url = "https://api.telegram.org/bot<Token>/sendPhoto";
    remote_image = requests.get(img_url)
    photo = io.BytesIO(remote_image.content)
    photo.name = 'img.png'
    files = {'photo': photo}
    data = {'chat_id' : "YOUR_CHAT_ID"}
    r= requests.post(url, files=files, data=data)
    print(r.status_code, r.reason, r.content)
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Anthone
3楼-- · 2020-02-16 05:20

Before sending the photo, you have to do output.seek(0) to put the cursor back to the beginning of the file, else it will be read as zero

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看我几分像从前
4楼-- · 2020-02-16 05:40

The solution is

elif 'Hi' in text:
reply(img=urllib2.urlopen('img url').read())

or

if text == 'help':
            reply(img=urllib2.urlopen('img url').read())
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欢心
5楼-- · 2020-02-16 05:41

I understand the question. Here's the answer:

        def sendImageFromUrl(url):
            #this tweak added if request image failed
            headers = {'user-agent': 'Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.0.7) Gecko/2009021910 Firefox/3.0.7'}
            response = requests.get(url, headers=headers)
            #response = requests.get(url)
            output = StringIO(response.content)
            img = Image.open(output)
            img.save(output, 'JPEG')
            resp = multipart.post_multipart(BASE_URL + 'sendPhoto', [
                ('chat_id', str(chat_id)),
                ('caption', 'Your Caption'),
            ], [
                ('photo', 'image.jpg', output.getvalue()),
            ])

Make sure your server does have python module: requests.

You can download here: https://pypi.python.org/pypi/requests#downloads

And put in your application like this

/myapp/app.yaml
/myapp/main.py
/myapp/requests/packages/
/myapp/requests/__init__.py
/myapp/requests/adapters.py
etc...

Credit: https://stackoverflow.com/a/17128168/1097372

Put in main.py after line 10

import requests
from StringIO import StringIO
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