Generate multivariate normal r.v.'s with rank-

Question

I'm just beating my head against the wall trying to get a Cholesky decomposition to work in order to simulate correlated price movements.

I use the following code:

cormat <- as.matrix(read.csv("http://pastebin.com/raw/qGbkfiyA"))
cormat <- cormat[,2:ncol(cormat)]
rownames(cormat) <- colnames(cormat)
cormat <- apply(cormat,c(1,2),FUN = function(x) as.numeric(x))

chol(cormat)
#Error in chol.default(cormat) : 
#    the leading minor of order 8 is not positive definite

cholmat <- chol(cormat, pivot=TRUE)
#Warning message:
#    In chol.default(cormat, pivot = TRUE) :
#    the matrix is either rank-deficient or indefinite

rands <- array(rnorm(ncol(cholmat)), dim = c(10000,ncol(cholmat)))
V <- t(t(cholmat) %*% t(rands))

#Check for similarity
cor(V) - cormat  ## Not all zeros!

#Check the standard deviations
apply(V,2,sd) ## Not all ones!

I'm not really sure how to properly use the pivot = TRUE statement to generate my correlated movements. The results look totally bogus.

Even if I have a simple matrix and I try out "pivot" then I get bogus results...

cormat <- matrix(c(1,.95,.90,.95,1,.93,.90,.93,1), ncol=3)

cholmat <- chol(cormat)
# No Error

cholmat2 <- chol(cormat, pivot=TRUE)
# No warning... pivot changes column order

rands <- array(rnorm(ncol(cholmat)), dim = c(10000,ncol(cholmat)))
V <- t(t(cholmat2) %*% t(rands))

#Check for similarity
cor(V) - cormat  ## Not all zeros!

#Check the standard deviations
apply(V,2,sd) ## Not all ones!

Answer 1

There are two errors with your code:

1. You did not use pivoting index to revert the pivoting done to the Cholesky factor. Note, pivoted Cholesky factorization for a semi-positive definite matrix A is doing:

   P'AP = R'R
   

   where P is a column pivoting matrix, and R is an upper triangular matrix. To recover A from R, we need apply the inverse of P (i.e., P'):

   A = PR'RP' = (RP')'(RP')
   

   Multivariate normal with covariance matrix A, is generated by:

   XRP'
   

   where X is multivariate normal with zero mean and identity covariance.

2. Your generation of X

   X <- array(rnorm(ncol(R)), dim = c(10000,ncol(R)))
   

   is wrong. First, it should not be ncol(R) but nrow(R), i.e., the rank of X, denoted by r. Second, you are recycling rnorm(ncol(R)) along columns, and the resulting matrix is not random at all. Therefore, cor(X) is never close to an identity matrix. The correct code is:

   X <- matrix(rnorm(10000 * r), 10000, r)
   

---

As a model implementation of the above theory, consider your toy example:

A <- matrix(c(1,.95,.90,.95,1,.93,.90,.93,1), ncol=3)

We compute the upper triangular factor (suppressing possible rank-deficient warnings) and extract inverse pivoting index and rank:

R <- suppressWarnings(chol(A, pivot = TRUE))
piv <- order(attr(R, "pivot"))  ## reverse pivoting index
r <- attr(R, "rank")  ## numerical rank

Then we generate X. For better result we centre X so that column means are 0.

X <- matrix(rnorm(10000 * r), 10000, r)
## for best effect, we centre `X`
X <- sweep(X, 2L, colMeans(X), "-")

Then we generate target multivariate normal:

## compute `V = RP'`
V <- R[1:r, piv]

## compute `Y = X %*% V`
Y <- X %*% V

We can verify that Y has target covariance A:

cor(Y)
#          [,1]      [,2]      [,3]
#[1,] 1.0000000 0.9509181 0.9009645
#[2,] 0.9509181 1.0000000 0.9299037
#[3,] 0.9009645 0.9299037 1.0000000

A
#     [,1] [,2] [,3]
#[1,] 1.00 0.95 0.90
#[2,] 0.95 1.00 0.93
#[3,] 0.90 0.93 1.00