Merge data.frames with duplicates

2020-02-14 05:43发布

I have many data.frames, for example:

df1 = data.frame(names=c('a','b','c','c','d'),data1=c(1,2,3,4,5))
df2 = data.frame(names=c('a','e','e','c','c','d'),data2=c(1,2,3,4,5,6))
df3 = data.frame(names=c('c','e'),data3=c(1,2))

and I need to merge these data.frames, without delete the name duplicates

> result
  names data1 data2 data3
1  'a'    1    1      NA
2  'b'    2    NA     NA
3  'c'    3    4      1
4  'c'    4    5      NA
5  'd'    5    6      NA
6  'e'    NA   2      2       
7  'e'    NA   3      NA

I cant find function like merge with option to handle with name duplicates. Thank you for your help. To define my problem. The data comes from biological experiment where one sample have a different number of replicates. I need to merge all experiment, and I need to produce this table. I can't generate unique identifier for replicates.

3条回答
该账号已被封号
2楼-- · 2020-02-14 05:49

See other questions:

Examples:

library(reshape)
out <- merge_recurse(L)

or

library(plyr)

out<-join(df1, df2, type="full")
out<-join(out, df3, type="full")
*can be looped

or

library(plyr)
out<-ldply(L)
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叼着烟拽天下
3楼-- · 2020-02-14 05:55

First define a function, run.seq, which provides sequence numbers for duplicates since it appears from the output that what is desired is that the ith duplicate of each name in each component of the merge be associated. Then create a list of the data frames and add a run.seq column to each component. Finally use Reduce to merge them all.

run.seq <- function(x) as.numeric(ave(paste(x), x, FUN = seq_along))

L <- list(df1, df2, df3)
L2 <- lapply(L, function(x) cbind(x, run.seq = run.seq(x$names)))

out <- Reduce(function(...) merge(..., all = TRUE), L2)[-2]

The last line gives:

> out
  names data1 data2 data3
1     a     1     1    NA
2     b     2    NA    NA
3     c     3     4     1
4     c     4     5    NA
5     d     5     6    NA
6     e    NA     2     2
7     e    NA     3    NA

EDIT: Revised run.seq so that input need not be sorted.

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不美不萌又怎样
4楼-- · 2020-02-14 06:06

I think there is just not enough information in your example data frames to do this. Which 'c' in dataframe 1 should be paired with which 'c' in data frame 2? We cannot tell, so R can't either. I suspect you will have to add another variable to each of your dataframes that uniquely identifies these duplicate cases.

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