Insert multiple rows to database from HTML form us

2020-02-13 06:57发布

站内问答 / PHP
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I'm trying to make a form that uses arrays so once it is submitted and processed multiple rows get inserted into my database. My main program is more complex than below but I could not get it working so I decides to create a small simple program to understand the basic syntax better then apply the techniques to the main program. I have got it to work using the depreciated MySQL but converting it to MySQLi is causing problems that I wonder if I can get help with.

My form is set up like this

<html>
<title>multi row insert test form</title>
<body>
<table>
<form action="process2.php" method="post">
<tr>
<th>forename</th>
<th>surname</th>
<th>level</th>
</tr>
<tr>
<td><input type="text" name="fname[]"></td>
<td><input type="text" name="sname[]"></td>
<td> 
<select name="level[]">
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
</select> 
</td>
</tr>
<tr>
<td><input type="text" name="fname[]"></td>
<td><input type="text" name="sname[]"></td>
<td> 
<select name="level[]">
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
</select> 
</td>
</tr>
<tr>
<td><input type="submit" name="submit" value="Submit"></td>
</tr>
</form>
</table>
</body>
</html>

and the php page that updates the database using MySQLi is as below

<?php
include 'dbconnect2.php';
$fname = $_POST['fname'];
$sname = $_POST['sname'];
$level = $_POST['level'];


if ($stmt = $mysqli->prepare("INSERT INTO people (fname, sname, level) values (?, ?, ?)")) {

$stmt->bind_param('ssi', $fname, $sname, $level);

for ($i=0; $i<2; $i++)
{
$fname[$i] = $fname;
$sname[$i] = $sname;
$level[$i] = $level;

$stmt->execute();
echo "Done";
}

$stmt->close();
}
?>

标签： php html mysqli
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3条回答
我只想做你的唯一
2楼-- · 2020-02-13 07:27

Or, with less rewriting your existing code:

$fnames = $_POST['fname'];
$snames = $_POST['sname'];
$levels = $_POST['level'];

$stmt = $mysqli->prepare("INSERT INTO people (fname, sname, level) values (?, ?, ?)")

for ($i=0; $i<count($fnames); $i++) {
    $fname = $fnames[$i];
    $sname = $snames[$i];
    $level = $levels[$i];
    $stmt->bind_param('ssi', $fname, $sname, $level);

    $stmt->execute();
}
echo "Done";

$stmt->close();
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干净又极端
3楼-- · 2020-02-13 07:29

It looks like you merely got your declaration syntax reversed in your loop.

Also, the first three declarations after your connection include are not necessary.

include 'dbconnect2.php';
$stmt = $mysqli->prepare("INSERT INTO people (fname, sname, level) VALUES (?, ?, ?)");
$stmt->bind_param('ssi', $fname, $sname, $level);
foreach ($_POST['fname'] as $index => $fname) {
    $sname = $_POST['sname'][$index];
    $level = $_POST['level'][$index];
    $stmt->execute();
}
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仙女界的扛把子
4楼-- · 2020-02-13 07:45

Try this. You need to iterate on all your post data, and bind them IN the loop.

include 'dbconnect2.php';
for ($i = 0; $i < count($fname); $i++) {
    $stmt = $mysqli->prepare("INSERT INTO people (fname, sname, level) values (?, ?, ?)");
    $stmt->bind_param('ssi', $_POST["fname"][$i], $_POST["sname"][$i], $_POST["level"][$i]);
    $stmt->execute();
}
echo "Done";
$stmt->close();
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