Based on "IEEE" spec :
"When either an input or result is NaN, this standard does not interpret the sign of a NaN."
However the printf
prints NaN
values as signed:nan
or -nan
Can someone point me the set of rules(from spec?) when nan
and when -nan
is printed
For example , I checked that printf(-1.0f)
prints -nan
Thank you
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The underlying representation of a NaN contains a sign bit, and this is what
printf
looks at when deciding if it should print the minus or not.The reason why the standard says that the sign bit should be ignored is to allow things like negate or absolute to simply modify the sign bit, without being forced to check if the input value was NaN.