I'm trying to code an algorithm that creates a legal Sudoku board in either Java or Javascript. Neither work, and I'm not entirely sure why.
Essentially, the problem in both programs is that either x or y is getting incremented more than it should (skipping the square). I can't for the life of me figure out how this is happening. I can provide the HTML that completes the JS solution if need be.
My best guess is it has to do with how I've created a stack using recursion, but as far as I can tell, it should work. In my old code there was an incorrect for loop, I'm aware of this. I pasted an old version, it's fixed now.
Java:
import java.util.*;
public class SudokuGenerator
{
//credit:cachao
//http://stackoverflow.com/questions/9959172/recursive-solution-to-sudoku-generator
public static final int BOARD_WIDTH = 9;
public static final int BOARD_HEIGHT = 9;
public SudokuGenerator() {
board = new int[BOARD_WIDTH][BOARD_HEIGHT];
}
//Recursive method that attempts to place every number in a square
public int[][] nextBoard()
{
nextBoard(0,0);
return board;
}
public void nextBoard(int x, int y)
{
int nextX = x;
int nextY = y;
//int[] toCheck = Collections.shuffle(Arrays.asList({1,2,3,4,5,6,7,8,9}));
int[] toCheck = {1,2,3,4,5,6,7,8,9};
Collections.shuffle(Arrays.asList(toCheck));
for(int i=0;i<toCheck.length;i++)
{
if(legalMove(x, y, toCheck[i]))
{
board[x][y] = toCheck[i];
if(x == 8)
{
if(y == 8)
break;//We're done! Yay!
else
{
nextX = 0;
nextY++;
}
}
else
{
nextX++;
}
nextBoard(nextX, nextY);
}
}
board[x][y] = 0;
}
public boolean legalMove(int x, int y, int current) {
for(int i=0;i<9;i++) {
if(current == board[x][i])
return false;
}
for(int i=0;i<9;i++) {
if(current == board[i][y])
return false;
}
int cornerX = 0;
int cornerY = 0;
if(x > 2)
if(x > 5)
cornerX = 6;
else
cornerX = 3;
if(y > 2)
if(y > 5)
cornerY = 6;
else
cornerY = 3;
for(int i=cornerX;i<10 && i<cornerX+3;i++)
for(int j=cornerY;j<10 && j<cornerY+3;j++)
if(current == board[i][j])
return false;
return true;
}
public void print()
{
for(int i=0;i<9;i++)
{
for(int j=0;j<9;j++)
System.out.print(board[i][j] + " ");
System.out.println();
}
}
public static void main(String[] args)
{
SudokuGenerator sg = new SudokuGenerator();
sg.nextBoard();
sg.print();
}
int[][] board;
}
Javascript:
//Recursive method that attempts to place every number in a square
function driver()
{
board = new Array(10);
for(var i=0;i<9;i++)
board[i] = new Array(10);
nextBoard(0,0);
print();
}
function nextBoard(x, y)
{
var nextX = x;
var nextY = y;
for(var i=1;i<10;i++) {
console.log(y + " " + x + " " + i);
document.getElementById(y + " " + x).innerHTML = i;
if(legalMove(x, y, i)) {
board[x][y] = i;
if(x === 8) {
if(y === 8)
return board;//We're done! Yay!
else {
nextX = 0;
nextY++;
}
}
else
nextX++;
nextBoard(nextX, nextY);
}
}
//This is needed for legalMove to work, otherwise [x][y] == 9
board[x][y] = undefined;
}
function legalMove(x, y, current) {
for(var i=0;i<9;i++) {
if(current === board[x][i])
return false;
}
for(var i=0;i<9;i++) {
if(current === board[i][y])
return false;
}
var cornerX = 0;
var cornerY = 0;
if(x > 2)
if(x > 5)
cornerX = 6;
else
cornerX = 3;
if(y > 2)
if(y > 5)
cornerY = 6;
else
cornerY = 3;
for(var i=cornerX;i<10 && i<cornerX+3;i++)
for(var j=cornerY;j<10 && j<cornerY+3;j++)
if(current === board[i][j])
return false;
return true;
}
function print() {
for(var i=0;i<9;i++)
for(var j=0;j<9;j++)
{
document.getElementById(i + " " + j).innerHTML = board[i][j];
console.log(board[i][j]);
}
}
var board;
In the Java code: I'll translate it to psuedocode:
But what if you can't put any number there as it ends up being illegal (aka a board where you can't insert any number in a specific square)?
You don't address that. What you need to do is implement it via backtracking:
Java:
Your loop iterator in nextBoard range from 1 to 9. I don't think you meant that. Same in the function legalMove.... initialize cornerX and cornerY to 0.
Java:
You should initialize your
board
variable, you may want to initialize it in a constructor:I believe that your loop iterator in the function nextBoard it is wrong:
for(int i=1;i<10;i++){ ... }
I think that you want to iterate from 0 to 9.
In the function nextBoard, you also need to check the variable:
int[] toCheck = {1,2,3,4,5,6,7,8,9};
You get an
java.lang.ArrayIndexOutOfBoundsException
, you should initialize it from 0 to 8, otherwise you try to access the board row number 9 and you get a runtime error.Another problem that you need to solve is that x is being set to nine in
nextBoard()
function. Call the functionnextBoard(int x, int y)
"manually" with these parameteres:nextBoard(7,3)
and you will understand why x is being set to nine. Check specifically the values of the variablenextX
.I believe it will really help you if you use a debugger to check this kind of errors, here you have a nice tutorial with a video explanation(in case your are using the Eclipse IDE).
Hope it helps.
In Java array indexes are zero-based. In
nextBoard
you loop over1..9
fori
and use it as an index intotoCheck
which will skip the first element at index0
and go past the end of the array. This will throwArrayIndexOutOfBoundsException
if the line containingtoCheck[i]
is reached withi
equal to9
.interesting question, I just noticed this one bug in the Java code: isn't the call to Collection.shuffle() useless since the toCheck array will remain unmodifed (unshuffled) after this call? Here is my quick fix (and I'm sure there are more clever ways to do it):