return (a) vs. return a

Question

I have seen both in the C and C++ code I have been looking at.

What is the difference?

Answer 1

Writing return x indicates a programmer who understands what return means. Whereas return(x) indicates a programmer who incorrectly believes that return is a kind of function.

Answer 2

return is not a function.

It is more a point of style. I personally do not use parentheses in a return statement unless it is showing order of operations.

examples

return a;
return (a || b);
return (a && (b || c));
return (a ? b : c);

Answer 3

No difference at all.

The official syntax is return something; or return; and of course it is a keyword, not a function.

For this reason you should not read it as return( a ); but as return (a); I think the difference is subtle but clear, parentheses will not apply to return but to a.

((((a)))) is the same as (a) that is the same as a.

You can also write something like...

int x = (((100)));

You can also write something like...

printf("%d\n", (z));

As someone said in the comments, there is now, with C++11 (2011 version of the C++ language) the new operator decltype. This operator introduces a new example where (a) is different from a, this is quite esoteric and a little out of topic but I add this example just for the purpose of completeness.

    int x = 10;
    decltype(x) y = x;   // this means int y = x;
    decltype((x)) z = x; // this means int& z = x;
    y = 20;
    z = 30;
    std::cout << x << " " << y << " " << z << std::endl;
    // this will print out "30 20 30"

Students will not be interested in this, as I said, too esoteric, and it will work only with compilers that supports at least part of the C++11 standard (like GCC 4.5+ and Visual Studio 2010).

This goes in contrast also with the use of typeid keyword:

int a;
std::cout << typeid(a).name() << std::endl; // will print "int"
std::cout << typeid((a)).name() << std::endl; // will print "int" !!!!