Groovy range with a 0.5 step size

Question

What's the most elgant way in Groovy to specify a range of integers and the 0.5 steps between them? e.g.: 1, 1.5, 2, 2.5, 3, 3.5, 4

Edit: To clarify: As an end result I need a range object for use in a Grails constraint. Though I suppose a list would be OK too.

Answer 1

(1..7).collect{0.5*it} is the best I can think of

Answer 2

my answer is the following:

(1..4).step(0.5)

Answer 3

A little late, but this works too

A one-liner for your above set:

(2..8)*.div(2)

Answer 4

Soo, to build on above. To test if a value val is in the range 1..n but with half values:

def range = 2..(n*2).collect { return it/2.0 }
return range.contains( val )

Something like that would work, but isn't as pretty as I'd like, but it lets you build the range once and use it multiple times, if you need that.

Answer 5

FYI, as of Groovy 1.6.0, it seems not to support natively. There exists only ObjectRange.step(int) at the moment.

http://groovy.codehaus.org/api/groovy/lang/ObjectRange.html#step%28int%29

Answer 6

def r = []
(0..12).each() {
  r << it
  r << it + 0.5
}