Plot linear model in 3d with Matplotlib

2020-02-09 05:31发布

I'm trying to create a 3d plot of a linear model fit for a data set. I was able to do this relatively easily in R, but I'm really struggling to do the same in Python. Here is what I've done in R:

3d plot

Here's what I've done in Python:

from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np
import pandas as pd
import statsmodels.formula.api as sm

csv = pd.read_csv('http://www-bcf.usc.edu/~gareth/ISL/Advertising.csv', index_col=0)
model = sm.ols(formula='Sales ~ TV + Radio', data = csv)
fit = model.fit()

fit.summary()

fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')

ax.scatter(csv['TV'], csv['Radio'], csv['Sales'], c='r', marker='o')

xx, yy = np.meshgrid(csv['TV'], csv['Radio'])

# Not what I expected :(
# ax.plot_surface(xx, yy, fit.fittedvalues)

ax.set_xlabel('TV')
ax.set_ylabel('Radio')
ax.set_zlabel('Sales')

plt.show()

What am I doing wrong and what should I do instead?

Thank you.

2条回答
▲ chillily
2楼-- · 2020-02-09 06:03

Got it!

The problem that I talk about in the comments to mdurant's answer is that the surface is not plotted as a nice square pattern like these Combining scatter plot with surface plot.

I realized that the problem was my meshgrid, so I corrected both ranges (x and y) and used proportional steps for np.arange.

This allowed me to use the code provided by mdurant's answer and it worked perfectly!

Here's the result:

3d scatter plot with OLS plane

And here's the code:

from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np
import pandas as pd
import statsmodels.formula.api as sm
from matplotlib import cm

csv = pd.read_csv('http://www-bcf.usc.edu/~gareth/ISL/Advertising.csv', index_col=0)
model = sm.ols(formula='Sales ~ TV + Radio', data = csv)
fit = model.fit()

fit.summary()

fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')

x_surf = np.arange(0, 350, 20)                # generate a mesh
y_surf = np.arange(0, 60, 4)
x_surf, y_surf = np.meshgrid(x_surf, y_surf)

exog = pd.core.frame.DataFrame({'TV': x_surf.ravel(), 'Radio': y_surf.ravel()})
out = fit.predict(exog = exog)
ax.plot_surface(x_surf, y_surf,
                out.reshape(x_surf.shape),
                rstride=1,
                cstride=1,
                color='None',
                alpha = 0.4)

ax.scatter(csv['TV'], csv['Radio'], csv['Sales'],
           c='blue',
           marker='o',
           alpha=1)

ax.set_xlabel('TV')
ax.set_ylabel('Radio')
ax.set_zlabel('Sales')

plt.show()
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我只想做你的唯一
3楼-- · 2020-02-09 06:06

You were correct in assuming that plot_surface wants a meshgrid of coordinates to work with, but predict wants a data structure like the one you fitted with (the "exog").

exog = pd.core.frame.DataFrame({'TV':xx.ravel(),'Radio':yy.ravel()})
out = fit.predict(exog=exog)
ax.plot_surface(xx, yy, out.reshape(xx.shape), color='None')
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