Android ActionBar tabs set initially selected tab

Question

I have noticed that when using

actionBar.setSelectedNavigationItem(x)

in the onCreate() method of my Activity, the tab item at position 0 is always selected first and then the tab item at position x is loaded. This means that (since I'm using Fragments) 2 Fragments are loaded. One of them being unnecessary...

Here's my code:

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    // Determine which bundle to use; either the saved instance or a bundle
    // that has been passed in through an intent.
    Bundle bundle = getIntent().getExtras();
    if (bundle == null) {
        bundle = savedInstanceState;
    }

    // Initialize members with bundle or default values.
    int position;
    if (bundle != null) {
        position = bundle.getInt("selected_tab");
    } else {
        position = 0;
    }

    // Set the tabs.
    ActionBar actionBar = getActionBar();
    actionBar.setNavigationMode(ActionBar.NAVIGATION_MODE_TABS);

    Tab tab = actionBar
            .newTab()
            .setText("Tab 1")
            .setTabListener(
                    new TabListener<RendersGridFragment>(this, "1",
                            RendersGridFragment.class));
    actionBar.addTab(tab);

    tab = actionBar
            .newTab()
            .setText("Tab 2")
            .setTabListener(
                    new TabListener<RendersGridFragment>(this, "2",
                            RendersGridFragment.class));
    actionBar.addTab(tab);

    tab = actionBar
            .newTab()
            .setText("Tab 3")
            .setTabListener(
                    new TabListener<RendersGridFragment>(this, "3",
                            RendersGridFragment.class));
    actionBar.addTab(tab);

    actionBar.setSelectedNavigationItem(position);
}

It seems that the tab at position 0 is selected initially by default. But, as you can see, I'm passing bundles to make sure the last selected tab is still selected when the activity onCreate() method is run again.

For example, if the last selected tab is at position 2, the onCreate() runs and the tab at position is 0 is loaded, then the tab at position 2 is loaded.

How can I make sure the ActionBar doesn't select tab at position 0 first when using actionBar.setSelectedNavigationItem(position).

Answer 1

If you have 3 tabs (i.e. tab 0, tab 1, tab 2) and want tab 1 to be preselected. Do this:

for (int i = 0; i < mFragmentPagerAdapter.getCount(); i++) {
    boolean preselected = (i == 1);
    actionBar.addTab(actionBar.newTab().setText(
        mFragmentPagerAdapter.getPageTitle(i)).setTabListener(this), preselected);
}

You will be using:

public abstract void addTab (ActionBar.Tab tab, boolean setSelected)

as per this API specification.

Answer 2

Percy Vega's reply seems to be the best working solution.

    for (int i = 0; i < mSectionsPagerAdapter.getCount(); i++) {

        boolean preselected = (i == ErrorDetails.tab_id);
        actionBar.addTab(
                actionBar.newTab()
                        .setText(mSectionsPagerAdapter.getPageTitle(i))
                        .setTabListener(this),preselected);
    }

Answer 3

you can use below statment in activtiy onStart method:

protected void onStart() {
    super.onStart();
    actionBar.selectTab(mainTab);
}

which mainTab variable here is of type Tab. this way you need to define tabs as class-wide variables like this:

Tab mainTab, tab2,tab3;

@Override
protected void onCreate(Bundle savedInstanceState) {
    //add tabs to action bar
    ....
}

Answer 4

For any others looking to do this you can also set the tab to selected by setting the position and then set true or false to indicate which tab should be selected

actionBar.addTab(tab1, 0, false);
actionBar.addTab(tab2, 1, true);
actionBar.addTab(tab3, 2, false);

Here are the docs on this approach: http://developer.android.com/reference/android/app/ActionBar.html#addTab(android.app.ActionBar.Tab, int, boolean)

Answer 5

Use the other addTab calls to override this behaviour. You'll need to add the tab you want to be selected first (in your case, the tab at position 2). Relevant Javadoc

actionBar.addTab(tab2);
actionBar.addTab(tab0, 0, false);
actionBar.addTab(tab1, 1, false);

Answer 6

bkurzius' answer helped me to fix a problem I was having with the same issue.

What I did was:

private final String TAB_SELECTED = "tab_selected"
...
private int mTabSelected;
...
mTabSelected = savedInstanceState.getInt(TAB_SELECTED);
...
final ActionBar actionbar = getActionBar();
...
actionbar.addTab(tab1, mTabSelected == 0);
actionbar.addTab(tab2, mTabSelected == 1);
actionbar.addTab(tab3, mTabSelected == 2);
...
outState.putInt(TAB_SELECTED, getActionBar().getSelectedNavigationIndex());

This way, the setSelected parameter is true only if mTabSelected is equal to the tab's index.