How would you implement tail efficiently?

2020-02-08 16:05发布

What is the efficient way to implement tail in *NIX? I came up (wrote) with two simple solution, both using kind of circular buffer to load lines into circular structure (array | doubly linked circular list - for fun). I've seen part of older implementation in busybox and from what I understood, they used fseek to find EOF and then read stuff "backwards". Is there anything cleaner and faster out there? I got asked this on interview and asker did not look satisfied. Thank you in advance.

标签: c linux unix tail
4条回答
Luminary・发光体
2楼-- · 2020-02-08 16:41

/*This example implements the option n of tail command.*/

#define _FILE_OFFSET_BITS 64
#include <stdio.h>
#include <stdlib.h>
#include <fcntl.h>
#include <errno.h>
#include <unistd.h>
#include <getopt.h>

#define BUFF_SIZE 4096

FILE *openFile(const char *filePath)
{
  FILE *file;
  file= fopen(filePath, "r");
  if(file == NULL)
  {
    fprintf(stderr,"Error opening file: %s\n",filePath);
    exit(errno);
  }
  return(file);
}

void printLine(FILE *file, off_t startline)
{
  int fd;
  fd= fileno(file);
  int nread;
  char buffer[BUFF_SIZE];
  lseek(fd,(startline + 1),SEEK_SET);
  while((nread= read(fd,buffer,BUFF_SIZE)) > 0)
  {
    write(STDOUT_FILENO, buffer, nread);
  }
}

void walkFile(FILE *file, long nlines)
{
  off_t fposition;
  fseek(file,0,SEEK_END);
  fposition= ftell(file);
  off_t index= fposition;
  off_t end= fposition;
  long countlines= 0;
  char cbyte;

  for(index; index >= 0; index --)
  {
    cbyte= fgetc(file);
    if (cbyte == '\n' && (end - index) > 1)
    {
      countlines ++;
      if(countlines == nlines)
      {
    break;
      }
     }
    fposition--;
    fseek(file,fposition,SEEK_SET);
  }
  printLine(file, fposition);
  fclose(file);
}

int main(int argc, char *argv[])
{
  FILE *file;
  file= openFile(argv[2]);
  walkFile(file, atol(argv[1]));
  return 0;
}

/*Note: take in mind that i not wrote code to parse input options and arguments, neither code to check if the lines number argument is really a number.*/
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The star\"
3楼-- · 2020-02-08 16:48

Read backwards from the end of the file until N linebreaks are read or the beginning of the file is reached.

Then print what was just read.

I dont think any fancy datastructures are needed here.

Here is the source code of tail if you're interested.

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我想做一个坏孩纸
4楼-- · 2020-02-08 16:51

I don't think there are solutions different than "keep the latest N lines while reading forward the data" or "start from the end and go backwards until you read the Nth line".

The point is that you'd use one or the another based on the context.

The "go to the end and go backwards" is better when tail accesses a random access file, or when the data is small enough to be put on memory. In this case the runtime is minimized, since you scan the data that has to be outputted (so, it's "optimal")

Your solution (keep the N latest lines) is better when tail is fed with a pipeline or when the data is huge. In this case, the other solution wastes too much memory, so it is not practical and, in the case the source is slower than tail (which is probable) scanning all the file doesn't matter that much.

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beautiful°
5楼-- · 2020-02-08 16:53

First use fseek to find the end-of-file then subtract 512 and fseek to that offset, then read forward from there to end. Count the number of line-breaks because if there are too few you will have to do the same with a subtracted offset of 1024 ... but in 99% of cases 512 will be enough.

This (1) avoids reading the whole file forward and (2) the reason why this is probably more efficient than reading backwards from the end is that reading forward is typically faster.

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