“synonym of type is deprecated; in a future versio

Question

I installed TensorFlow 1.10.1 but when I tried to import TensorFlow it said that I need TensorFlow version 1.10.0. Thus, I installed it and now I get the following warnings:

>>> import tensorflow
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:516: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint8 = np.dtype([("qint8", np.int8, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:517: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint8 = np.dtype([("quint8", np.uint8, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:518: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint16 = np.dtype([("qint16", np.int16, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:519: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint16 = np.dtype([("quint16", np.uint16, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:520: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint32 = np.dtype([("qint32", np.int32, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:525: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  np_resource = np.dtype([("resource", np.ubyte, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:541: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint8 = np.dtype([("qint8", np.int8, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:542: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint8 = np.dtype([("quint8", np.uint8, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:543: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint16 = np.dtype([("qint16", np.int16, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:544: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint16 = np.dtype([("quint16", np.uint16, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:545: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint32 = np.dtype([("qint32", np.int32, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:550: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  np_resource = np.dtype([("resource", np.ubyte, 1)])

Answer 1

It just a warning, not an error. It occurring because your current numpy libray version is not compatible with tensorflow version. You need to downgrade numpy version.

tensorflow 1.10.0 has requirement numpy<=1.14.5,>=1.13.3, but you must have some higher version installed(this warning message occurs with newest numpy version 1.17.0).

Answer 2

I had the same problem in my linux laptop with tensorflow in python3 v3.6

Actually, you just need to change some lines in 2 files :

• 1

  ~/.local/lib/python3.6/site-packages/tensorflow/python/framework/dtypes.py

in your case :

C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py

now change this code : (line 516)

_np_qint8 = np.dtype([("qint8", np.int8, 1)])
_np_quint8 = np.dtype([("quint8", np.uint8, 1)])
_np_qint16 = np.dtype([("qint16", np.int16, 1)])
_np_quint16 = np.dtype([("quint16", np.uint16, 1)])
_np_qint32 = np.dtype([("qint32", np.int32, 1)])


# _np_bfloat16 is defined by a module import.

# Custom struct dtype for directly-fed ResourceHandles of supported type(s).
np_resource = np.dtype([("resource", np.ubyte, 1)])

by this code :

_np_qint8 = np.dtype([("qint8", np.int8, (1,))])
_np_quint8 = np.dtype([("quint8", np.uint8, (1,))])
_np_qint16 = np.dtype([("qint16", np.int16, (1,))])
_np_quint16 = np.dtype([("quint16", np.uint16, (1,))])
_np_qint32 = np.dtype([("qint32", np.int32, (1,))])

# _np_bfloat16 is defined by a module import.

# Custom struct dtype for directly-fed ResourceHandles of supported type(s).
np_resource = np.dtype([("resource", np.ubyte, (1,))])

you have to do the same on this file :

• 2

  ~/.local/lib/python3.6/site-packages/tensorboard/compat/tensorflow_stub/dtypes.py

in your case :

C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard/compat/tensorflow_stub/dtypes.py

and it will work.

Answer 3

If you're using TF 2.0 a quick solution would be to downgrade your numpy to 1.16.4. (I used 1.17 and received the same warning messages).

1. pip uninstall numpy 
2. pip install numpy==1.16.4

See here (thanks to ymodak)

Answer 4

The newest numpy release notes (1.17) has:

Future Changes

Shape-1 fields in dtypes won’t be collapsed to scalars in a future version
Currently, a field specified as [(name, dtype, 1)] or "1type" is interpreted 
as a scalar field (i.e., the same as [(name, dtype)] or [(name, dtype, ()]). 
This now raises a FutureWarning; in a future version, it will be interpreted 
as a shape-(1,) field, i.e. the same as [(name, dtype, (1,))] or "(1,)type" 
(consistently with [(name, dtype, n)] / "ntype" with n>1, which is already 
equivalent to [(name, dtype, (n,)] / "(n,)type").

https://docs.scipy.org/doc/numpy/release.html

Thus with your expression:

In [123]: np.dtype([("qint8", np.int8, 1)])                                                                  
/usr/local/bin/ipython3:1: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  #!/usr/bin/python3
Out[123]: dtype([('qint8', 'i1')])

In [124]: np.dtype([("qint8", np.int8, (1,))])                                                               
Out[124]: dtype([('qint8', 'i1', (1,))])

In [125]: np.dtype([("qint8", np.int8)])                                                                     
Out[125]: dtype([('qint8', 'i1')])

In [126]: np.dtype([("qint8", np.int8, 2)])                                                                  
Out[126]: dtype([('qint8', 'i1', (2,))])

In [127]: np.__version__                                                                                     
Out[127]: '1.17.0'

Answer 5

It is happening because of your TensorFlow version is incompatible with numpy. Try reinstalling numpy's previous versions. In my case I tried 1.16.4 : pip install numpy==1.16.4

But first, you need to shutdown all running kernals and uninstall numpy with : pip uninstall numpy

Answer 6

pip install "numpy<1.17"

To revert to Numpy version 1.16.4