Given a pandas Series that represents frequencies

2020-02-07 17:13发布

I was experimenting with the kaggle.com Titanic data set (data on every person on the Titanic) and came up with a gender breakdown like this:

gender = df.sex.value_counts()
gender

male   577
female 314 

I would like to find out the percentage of each gender on the Titanic.

My approach is slightly less than ideal:

from __future__ import division
pcts = gender / gender.sum()
pcts

male      0.647587
female    0.352413

Is there a better (more idiomatic) way?

Thanks!

标签: python pandas
4条回答
闹够了就滚
2楼-- · 2020-02-07 18:02

This function is implemented in pandas, actually even in value_counts(). No need to calculate :)

just type:

df.sex.value_counts(normalize=True)

which gives exactly the desired output.

Please note that value_counts() excludes NA values, so numbers might not add up to 1. See here: http://pandas-docs.github.io/pandas-docs-travis/generated/pandas.Series.value_counts.html (A column of a DataFrame is a Series)

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萌系小妹纸
3楼-- · 2020-02-07 18:05

I know it is an old post, but I hope this answer's gonna help someone in the future. In case you wish to show percentage one of the things that you might do is use value_counts(normalize=True) as answered above by @fanfabbb.

With that said, for many purposes, you might want to show it in the percentage out of a hundred. that can be achieved like so

gender = df.sex.value_counts(normalize=True).mul(100).round(1).astype(str) + '%'

In this case, we multiply the results by hundred, round it to one decimal point and add the percentage sign.

Hope it could help:)

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家丑人穷心不美
4楼-- · 2020-02-07 18:08

If you want to merge counts with percentage, can use:

c = df.sex.value_counts(dropna=False)
p = df.sex.value_counts(dropna=False, normalize=True)
pd.concat([c,p], axis=1, keys=['counts', '%'])
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够拽才男人
5楼-- · 2020-02-07 18:09

I think I would probably do this in one go (without importing division):

1. * df.sex.value_counts() / len(df.sex)

or perhaps, remembering you want a percentage:

100. * df.sex.value_counts() / len(df.sex)

Much of a muchness really, your way looks fine too.

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