Why does NVL always evaluate 2nd parameter

2020-02-07 00:40发布

Does anyone know, why Oracle's NVL (and NVL2) function always evaluate the second parameter, even if the first parameter is not NULL?

Simple test:

CREATE FUNCTION nvl_test RETURN NUMBER AS
BEGIN
  dbms_output.put_line('Called');
  RETURN 1;
END nvl_test;

SELECT NVL( 0, nvl_test ) FROM dual

returns 0, but also prints Called.

nvl_test has been called, even though the result is ignored since first parameter is not NULL.

标签: sql oracle nvl
4条回答
beautiful°
2楼-- · 2020-02-07 01:22

Here is a post where Tom Kyte confirms that decode and case short circuit but not nvl but he doesn't give justification or documentation for why. Just states it to be:

http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:926029357278#14932880517348

So in your case you should use decode or case instead of nvl if an expensive function will be called in your query.

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仙女界的扛把子
3楼-- · 2020-02-07 01:37

In general, it would make sense that the second parameter is evaluated before calling the function, because in general that is how functions are called: all arguments to the function are evaluated and the evaluated values are sent to the function.

However, in the case of a very common system function like NVL, I would have thought PL/SQL could optimise, treating the function call as a special case. But perhaps that is more difficult than it sounds (to me), as I'm sure this optimisation would have occurred to the developers of Oracle.

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孤傲高冷的网名
4楼-- · 2020-02-07 01:41

It's always been that way, so Oracle has to keep it that way to remain backwards compatible.

Use COALESCE instead to get the short-circuit behaviour.

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劫难
5楼-- · 2020-02-07 01:44

They are obviously not short-circuiting, but I can't find any references in Oracle documentation.

Check out this discussion: http://forums.oracle.com/forums/thread.jspa?messageID=3478040

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