I am trying to understand the behavior of the @() array constructor, and I came across this very strange test.
It seems that the value of an empty pipeline is "not quite" the same as $null, even though it is -eq $null
The output of each statement is shown after the ###
$y = 1,2,3,4 | ? { $_ -ge 5 }
$z = $null
if ($y -eq $null) {'y is null'} else {'y NOT null'} ### y is null
if ($z -eq $null) {'z is null'} else {'z NOT null'} ### z is null
$ay = @($y)
$az = @($z)
"ay.length = " + $ay.length ### ay.length = 0
"az.length = " + $az.length ### az.length = 1
$az[0].GetType() ### throws exception because $az[0] is null
So the $az array has length one, and $az[0] is $null.
But the real question is: how is it possible that both $y and $z are both -eq $null, and yet when I construct arrays with @(...) then one array is empty, and the other contains a single $null element?
Expanding on Frode F.'s answer, "nothing" is a mostly magical value in PowerShell - it's called [System.Management.Automation.Internal.AutomationNull]::Value. The following will work similarly:
PowerShell treats the value AutomationNull.Value like $null in most places, but not everywhere. One notable example is in a pipeline:
This will only print:
Note that expressions are themselves pipelines even if you don't have a pipeline character, so the following are roughly equivalent:
Understanding this, it should be clear that if $y holds the value AutomationNull.Value, nothing is written to the pipeline, and hence the array is empty.
One might ask why $null is written to the pipeline. It's a reasonable question. There are some situations where scripts/cmdlets need to indicate "failed" without using exceptions - so "no result" must be different, $null is the obvious value to use for such situations.
I've never run across a scenario where one needs to know if you have "no value" or $null, but if you did, you could use something like this:
The reason you're experiencing this behaviour is becuase
$null
is a value. It's a "nothing value", but it's still a value.The way
@()
works, is that it guarantees that the result is delievered inside a wrapper(an array). This means that as long as you have one or more objects, it will wrap it inside an array(if it's not already in an array like multiple objects would be).$y
is nothing, it's a reference, but no variable data was stored. So there is nothing to create an array with.$z
however, IS a stored variable, with nothing(null-object) as the value. Since this object exists, the array constructor can create an array with that one item.