I want to create a generic class that has a member of type T
. T
may be a class, a nullable class, a struct, or a nullable struct. So basically anything. This is a simplified example that shows my problem:
#nullable enable
class Box<T> {
public T Value { get; }
public Box(T value) {
Value = value;
}
public static Box<T> CreateDefault()
=> new Box<T>(default(T));
}
Due to using the new #nullable enable
feature I get the following warning: Program.cs(11,23): warning CS8653: A default expression introduces a null value when 'T' is a non-nullable reference type.
This warning makes sense to me. I then tried to fix it by adding a ?
to the property and constructor parameter:
#nullable enable
class Box<T> {
public T? Value { get; }
public Box(T? value) {
Value = value;
}
public static Box<T> CreateDefault()
=> new Box<T>(default(T));
}
But now I get two errors instead:
Program.cs(4,12): error CS8627: A nullable type parameter must be known to be a value type or non-nullable reference type. Consider adding a 'class', 'struct', or type constraint.
Program.cs(6,16): error CS8627: A nullable type parameter must be known to be a value type or non-nullable reference type. Consider adding a 'class', 'struct', or type constraint.
However, I don't want to add a constraint. I don't care if T
is a class or a struct.
An obvious solution is to wrap the offending members under a #nullable disable
directive. However, like #pragma warning disable
, I'd like to avoid doing that unless it's necessary. Is there another way in getting my code to compile without disabling the nullability checks or the CS8653 warning?
$ dotnet --info
.NET Core SDK (reflecting any global.json):
Version: 3.0.100-preview4-011223
Commit: 118dd862c8
Jeff Mercado raised a good point in the comments:
For example,
default(T)
forT = string
would benull
, since at runtime there is no distinction betweenstring
andstring?
. This is a current limitation of the language feature.I have worked around this limation by creating separate
CreateDefault
methods for each case:This seems type safe to me, at the cost of more ugly call sites (
CreateDefaultBox.ReferenceTypeNullable<object>()
instead ofBox<object?>.CreateDefault()
). In the example class I posted I'd just remove the methods completely and use theBox
constructor directly. Oh well.What does null! statement mean?
As discussed in the comments on this question, you will probably need to take some thought as to whether a
Box<string>
with a default value is valid or not in a nullable context and potentially adjust your API surface accordingly. Perhaps the type has to beBox<string?>
in order for an instance containing a default value to be valid. However, there are scenarios where you will want to specify that properties, method returns or parameters, etc. could still be null even though they have non-nullable reference types. If you are in that category, you will probably want to make use of nullability-related attributes.The MaybeNull and AllowNull attributes have been introduced to .NET Core 3 to handle this scenario.
Some of the specific behaviors of these attributes are still evolving, but the basic idea is:
[MaybeNull]
means that the output of something (reading a field or property, a method return, etc.) could benull
.[AllowNull]
means that the input to something (writing a field or property, a method parameter, etc.) could benull
.Notes:
[MaybeNull]
attribute from the propertyValue
we would not get a warning about assigning the[AllowNull] T value
parameter to it. The[AllowNull]
in practice just prevents possible-null-argument warnings from being given at the call site.default(T)
, but it may also happen at the invocation of generic methods whose returns are annotated with[MaybeNull]
. For now we handle the problem by suppressing the warning withdefault(T)!
.box.Value
because of the[MaybeNull]
annotation on the property.box.Value
is a non-nullable value type.Please see https://devblogs.microsoft.com/dotnet/try-out-nullable-reference-types for more information, particularly the section "the issue with T?".