Cancel all queued jQuery slideUp and slideDown ani

2020-02-03 06:09发布

I have an interface that makes heavy use of the jQuery slideUp and slideDown effect to expand items in a tri-state kind of way.

onmouseover: function() { 
this.find('.details', this).slideDown(); 
},
onmouseout: function() { 
this.find('.details', this).slideUp(); 
}

However, when the user quickly moves the mouse over these interface elements the animations can't keep up and the items will be sliding up and down long after the mouse has left the interface area.

Is there a way to cancel all the queued-up slide animations when the mouse leaves the item's container div?

7条回答
Emotional °昔
2楼-- · 2020-02-03 06:39

I believe you should be able to just add a .stop() and it'll take care of that for you:

onmouseover: function() { 
this.find('.details', this).stop().slideDown(); 
},
onmouseout: function() { 
this.find('.details', this).stop().slideUp(); 
}
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We Are One
3楼-- · 2020-02-03 06:40

Generally speaking you want to call stop() when starting such an animation:

$("...").hover(function() {
  $(this).stop().slideDown();
}, function() {
  $(this).stop().slideUp();
});

That should be sufficient to avoid long-running animation queues.

You can also use $.clearQueue() to globally clear animations that haven't yet begun.

Also, if you're setting these on mouseover() and mouseout() it is arguably clearer to simply use the hover() event instead.

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叼着烟拽天下
4楼-- · 2020-02-03 06:40

In my case, I was also looking for a .stop() solution to the up and down extensive animation queue. However, it still didn't solve, because it wasn't smooth, and it was buggy, making it not to slide down anymore.

Hence, I came with a solution that is not related to cancel queues, but it might help some of you. The solution is about sliding it down or up just when the animation target is not currently being animated.

$("#trigger").on({
    mouseover: function() {
        $("#animationTarget").not(":animated").slideDown();
    },
    mouseleave: function() {
        $("#animationTarget").not(":animated").slideUp();
    }
});
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姐就是有狂的资本
5楼-- · 2020-02-03 06:41

It is also much better if you put parameters in stop(), just like this: stop(true,true)...

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太酷不给撩
6楼-- · 2020-02-03 06:42

You could do something like the following: http://jsfiddle.net/3o2bsxo6/3/

JavaScript

$('h5').each(function(){
    $(this).unbind('mouseover'); //unbind previous events (prevent repeats)
    $(this).unbind('mouseout');

    $(this).on('mouseover',function(){
        if(!$(this).next('.details').is(':visible')){ //if not visible
             $(this).next('.details').slideDown();   //slidedown                        
        }
    })  
    $(this).on('mouseout',function(){
        if($(this).next('.details').is(':visible')){ //if visible
             $(this).next('.details').slideUp();    //slideup                           
        }
    })      
})

html:

<h5>Hover To Slide</h5>
<p class="details">
However, when the user quickly moves the mouse over these interface elements the animations can't keep up and the items will be sliding up and down long after the mouse has left the interface area.    
</p>
<h5>Hover To Slide</h5>
<p class="details">
However, when the user quickly moves the mouse over these interface elements the animations can't keep up and the items will be sliding up and down long after the mouse has left the interface area.    
</p>
<h5>Hover To Slide</h5>
<p>
However, when the user quickly moves the mouse over these interface elements the animations can't keep up and the items will be sliding up and down long after the mouse has left the interface area.    
</p>

CSS:

p{
    display:none;
}
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甜甜的少女心
7楼-- · 2020-02-03 06:44

The answer you really want is a combination of all the other three answers.

$("...").hover(function() {
  $(this).stop(true, true).slideDown();
}, function() {
  $(this).stop(true, true).slideUp();
});

You want the trues in the stop because these clear the pending animation queues. If you dont use these, you'll find moving the mouse quickly and repeatedly across the element will produce buggy results.

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