Find which rows have different values for a given

Question

I am trying to compare two addresses from the same ID to see whether they match. For example:

Id  Adress Code     Address
1   1               123 Main
1   2               123 Main
2   1               456 Wall
2   2               456 Wall
3   1               789 Right
3   2               100 Left

I'm just trying to figure out whether the address for each ID matches. So in this case I want to return just ID 3 as having a different address for Address Code 1 and 2.

Answer 1

You can do this using a group by:

select id, addressCode
from t
group by id, addressCode
having min(address) <> max(address)

Another way of writing this may seem clearer, but does not perform as well:

select id, addressCode
from t
group by id, addressCode
having count(distinct address) > 1

Answer 2

This works for PL/SQL:

select count(*), id,address from table group by id,address having count(*)<2

Answer 3

Join the table with itself and give it two different aliases (A and B in the following example). This allows to compare different rows of the same table.

SELECT DISTINCT A.Id
FROM
    Address A
    INNER JOIN Address B
        ON A.Id = B.Id AND A.[Adress Code] < B.[Adress Code]
WHERE
    A.Address <> B.Address

The "less than" comparison < ensures that you get 2 different addresses and you don't get the same 2 address codes twice. Using "not equal" <> instead, would yield the codes as (1, 2) and (2, 1); each one of them for the A alias and the B alias in turn.

The join clause is responsible for the pairing of the rows where as the where-clause tests additional conditions.

---

The query above works with any address codes. If you want to compare addresses with specific address codes, you can change the query to

SELECT A.Id
FROM
    Address A
    INNER JOIN Address B
        ON A.Id = B.Id
WHERE                     
    A.[Adress Code] = 1 AND
    B.[Adress Code] = 2 AND
    A.Address <> B.Address

I imagine that this might be useful to find customers having a billing address (Adress Code = 1 as an example) differing from the delivery address (Adress Code = 2) .

Answer 4

Personally, I would print them to a file using Perl or Python in the format

<COL_NAME>:  <COL_VAL>

for each row so that the file has as many lines as there are columns. Then I'd do a diff between the two files, assuming you are on Unix or compare them using some equivalent utilty on another OS. If you have multiple recordsets (i.e. more than one row), I would prepend to each file row and then the file would have NUM_DB_ROWS * NUM_COLS lines