I am trying to find intersection
of two lists based on some condition and doing some steps. Couldn't find a way to do it (in learning stage) :)
Double totalAmount = 0.00d;
Double discount = 0.00d;
List<OrderLineEntry> orderLineEntryList = orderEntry.getOrderReleases().stream()
.flatMap(orderReleaseEntry -> orderReleaseEntry.getOrderLines().stream())
.filter(orderLineEntry -> orderLineEntry.getStatus().equals("PP") || orderLineEntry.getStatus().equals("PD"))
.collect(Collectors.toList());
for (OrderLineEntry orderLineEntry : orderLineEntryList) {
for (SplitLineEntry splitLineEntry : splitReleaseEntry.getLineEntries()) {
if (splitLineEntry.getOrderLineId().equals(orderLineEntry.getId()) && splitLineEntry.getStatusCode() != "PX") {
totalAmount += orderLineEntry.getFinalAmount();
couponDiscount += orderLineEntry.getCouponDiscount() == null ? 0.00d : orderLineEntry.getCouponDiscount();
}
}
}
As you see, the logic is simple
Get All items from order based on some filter list
and intersect with another list
and do some stuff.
List intersect = list1.stream().filter(set1::contains).collect(Collectors.toList());
This will work where T is String, Integer, Float etc where equals, hashcode is fairly straightforward. But if the T is a custom object, we need to implement HashCode & equals
The simplest approach is this:
First build up a set of the fk_id;
You can avoid using a reference to an array object by using reduce function. e.g. see how Collectors.averagingDouble is implemented. But I find this more complicated.
Note: this is O(N) by using a set of ids rather than using a list of matching ids which would be O(N^2)