The compiler seems to be ok with this (single digit hex values only):
byte[] rawbytes={0xa, 0x2, 0xf};
But not this:
byte[] rawbytes={0xa, 0x2, 0xff};
I get a "Possible Loss of Precision found : int required : byte" error?
What am I doing wrong - or are single digit hex numbers a special case ?
Java 1.5.x.
As the other answered already said, byte is a signed type in Java. The range is from -128 to 127 inclusive. So 0xff is equal to -0x01. You can use 0xff instead of -0x01 if you add a manual cast:
There is one more possibility by declaring a helper function with variable arguments. This may be preferable if you need to declare multiple byte arrays.
Example code
byte
is signed and0xff = 255
is too big. The valid range is (-128 .. 127).Example code:
"0xFF" is an
int
literal for the decimal value 255, which isn't representable as a byte.For now, you'll need to cast it to a
byte
to tell the compiler you really mean -1, like this:It was proposed to add a new byte literal syntax (
y
orY
suffix) to Java 7. Then you would have been able to write:However, this proposal was not included in the "omnibus proposal for improved integral literals," so we be stuck with the cast forever.