GCC version 4.6
The Problem: To find a way to feed in parameters to the executable, say a.out
, from the command line - more specifically feed in an array of double precision numbers.
Attempt: Using the READ(*,*)
command, which is older in the standard:
Program test.f
-
PROGRAM MAIN
REAL(8) :: A,B
READ(*,*) A,B
PRINT*, A+B, COMMAND_ARGUMENT_COUNT()
END PROGRAM MAIN
The execution -
$ gfortran test.f
$ ./a.out 3.D0 1.D0
This did not work. On a bit of soul-searching, found that
$./a.out
3.d0,1.d0
4.0000000000000000 0
does work, but the second line is an input prompt, and the objective of getting this done in one-line is not achieved. Also the COMMAND_ARGUMENT_COUNT()
shows that the numbers fed into the input prompt don't really count as 'command line arguments', unlike PERL.
If you want to get the arguments fed to your program on the command line, use the (since Fortran 2003) standard intrinsic subroutine
GET_COMMAND_ARGUMENT
. Something like this might workNote:
get_command_argument
is a character variable which you'll have to parse to turn into a real (or whatever). Note also that I've allowed only 12 characters in each element of theargs
array, you may want to fiddle around with that.read
isn't used for reading command line arguments in Fortran programs.Since you want to read an array of real numbers, you might be better off using the approach you've already figured out, that is reading them from the terminal after the program has started, it's up to you.