Android OnClickListener - identify a button

2019-01-01 06:34发布

Hey. I have the activity:

public class Mtest extends Activity {
  Button b1;
  Button b2;
  public void onCreate(Bundle savedInstanceState) {
    ...
    b1 = (Button) findViewById(R.id.b1);
    b2 = (Button) findViewById(R.id.b2);
    b1.setOnClickListener(myhandler);
    b2.setOnClickListener(myhandler);
    ...
  }
  View.OnClickListener myhandler = new View.OnClickListener() {
    public void onClick(View v) {
      // MY QUESTION STARTS HERE!!!
      // IF b1 do this
      // IF b2 do this
      // MY QUESTION ENDS HERE!!!
    }
  }
}

How do I check which button has been clicked?

11条回答
柔情千种
2楼-- · 2019-01-01 06:53

I prefer:

class MTest extends Activity implements OnClickListener {
    public void onCreate(Bundle savedInstanceState) {
    ...
    Button b1 = (Button) findViewById(R.id.b1);
    Button b2 = (Button) findViewById(R.id.b2);
    b1.setOnClickListener(this);
    b2.setOnClickListener(this);
    ...
}

And then:

@Override
public void onClick(View v) {
    switch (v.getId()) {
        case R.id.b1:
            ....
            break;
        case R.id.b2:
            ....
            break;
    }   
}

Switch-case is easier to maintain than if-else, and this implementation doesn't require making many class variables.

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泛滥B
3楼-- · 2019-01-01 06:54

You will learn the way to do it, in an easy way, is:

public class Mtest extends Activity {
  Button b1;
  Button b2;
  public void onCreate(Bundle savedInstanceState) {
    ...
    b1 = (Button) findViewById(R.id.b1);
    b2 = (Button) findViewById(R.id.b2);
    b1.setOnClickListener(myhandler1);
    b2.setOnClickListener(myhandler2);
    ...
  }
  View.OnClickListener myhandler1 = new View.OnClickListener() {
    public void onClick(View v) {
      // it was the 1st button
    }
  };
  View.OnClickListener myhandler2 = new View.OnClickListener() {
    public void onClick(View v) {
      // it was the 2nd button
    }
  };
}

Or, if you are working with just one clicklistener, you can do:

View.OnClickListener myOnlyhandler = new View.OnClickListener() {
  public void onClick(View v) {
      switch(v.getId()) {
        case R.id.b1:
          // it was the first button
          break;
        case R.id.b2:
          // it was the second button
          break;
      }
  }
}

Though, I don't recommend doing it that way since you will have to add an if for each button you use. That's hard to maintain.

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孤独寂梦人
4楼-- · 2019-01-01 06:59

The best way is by switch-ing between v.getId(). Having separate anonymous OnClickListener for each Button is taking up more memory. Casting View to Button is unnecessary. Using if-else when switch is possible is slower and harder to read. In Android's source you can often notice comparing the references by if-else:

if (b1 == v) {
 // ...
} else if (b2 == v) {

I don't know exactly why they chose this way, but it works too.

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深知你不懂我心
5楼-- · 2019-01-01 06:59
Button mybutton = new Button(ViewPagerSample.this);
mybutton.setOnClickListener(new OnClickListener() {
    @Override
    public void onClick(View v) {
            // TODO Auto-generated method stub
    }
});
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长期被迫恋爱
6楼-- · 2019-01-01 07:00
Button button1 = (Button)findViewById(R.id.button1);
button1.setOnClickListener(this);

@Override
public void onClick(View v) {
    // TODO Auto-generated method stub
    if(v.getId() == R.id.button1){
        Toast.makeText(context, "Button 1 Click", Toast.LENGTH_LONG).show();
    }
}

Check this article for more details

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余生请多指教
7楼-- · 2019-01-01 07:06

use setTag();

like this:

@Override    
public void onClick(View v) {     
    int tag = (Integer) v.getTag();     
    switch (tag) {     
    case 1:     
        System.out.println("button1 click");     
        break;     
    case 2:     
        System.out.println("button2 click");     
       break;   
    }     
}     
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