How can I fix this error java.util.ConcurrentModif

2020-02-01 04:59发布

I get an error on the following line. I'm doing the process of adding to the jsonarray. Please help me.

jsonArr=new JSONArray();
if(req.getSession().getAttribute("userses")!=null){
    String name=(req.getParameter("name")==null?"":to_EnglishName(req.getParameter("name").toUpperCase()));
    if(!name.equals("")){
        for(Book c:GlobalObjects.bookList){
            if(c.getBookName().startsWith(name)){
                    jsonObjec=new JSONObject();
                    jsonObjec.put("label",c.getBookName());
                    jsonObjec.put("value", c.getId());
                    jsonArr.add(jsonObjec);//java.util.ConcurrentModificationException
            }
        }
    }
}
jsonArr.write(res.getWriter());

7条回答
贼婆χ
2楼-- · 2020-02-01 05:27

Also one more way is there, ie insted of passing actual list , we can pass clone of list for iteration.

listForIteration = list.clone();

//Do operation..

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\"骚年 ilove
3楼-- · 2020-02-01 05:30

This is an error I often met while reprogramming. the reason or detail of this exception are pretty clear. it is unallowed to modify the collection(you are adding a new element) while it is being iterated. At least the syntax for DO NOT support do that.

To fix your problem, there have two way I think it is simple.

1). rather than using for statement to loop over, the better way is to use iterator to avoid ConcurrentModificationException.

    Iterator<Book> iterator = bookList.iterator();
    while(iterator.hasNext()){
      Book c = iterator.next();
      if(c.getBookName().startsWith(name)){
                jsonObjec=new JSONObject();
                jsonObjec.put("label",c.getBookName());
                jsonObjec.put("value", c.getId());
                jsonArr.add(jsonObjec);
        }
    }

2). while looping it, don't add it.

     List list = new ArrayList<>();
     for(Book c:GlobalObjects.bookList){
        if(c.getBookName().startsWith(name)){
                jsonObjec=new JSONObject();
                jsonObjec.put("label",c.getBookName());
                jsonObjec.put("value", c.getId());
                list.add(jsonObjec);//java.util.ConcurrentModificationException
        }
     }
     jsonArr.addAll(list);
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狗以群分
4楼-- · 2020-02-01 05:38

You get ConcurrentModificationException when you are iterating over a collection and you modify the same collection within the loop. The given code snippet does not show that, so there is something else above or below modifying the collection. Try declaring the jsonArr right at the place where you instantiate it.

One possible reason could be the jsonArr instance Object is class level and is accessed by multiple threads. Declare the jsonArr object where it is instantiated.

Edit: Make jsonArr a local variable.

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聊天终结者
5楼-- · 2020-02-01 05:40

Or use a ListIterator which allows iterating and modifying the same list

http://docs.oracle.com/javase/6/docs/api/java/util/ListIterator.html

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劫难
6楼-- · 2020-02-01 05:43

just use java.util.concurrent.CopyOnWriteArrayList

List<String> empList = new CopyOnWriteArrayList<>();
empList.add("Mojtaba");
empList.add("Mojtabye");
empList.add("Yeganeh");

for (String item : empList) {
    System.out.println(item);
    empList.add("test");
}
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干净又极端
7楼-- · 2020-02-01 05:45

To fix this problem, make sure that If your collection is not thread safe then it must not get modified with another thread when some other thread is iterating over this collection.

There are two possible ways to fix this problem -

1) One solution is to synchronize all access to the collection

2) Use Thread safe collection like CopyOnWriteArrayList

From Java Doc -

This exception may be thrown by methods that have detected concurrent modification of an object when such modification is not permissible.

For example, it is not generally permssible for one thread to modify a Collection while another thread is iterating over it. In general, the results of the iteration are undefined under these circumstances. Some Iterator implementations (including those of all the collection implementations provided by the JRE) may choose to throw this exception if this behavior is detected. Iterators that do this are known as fail-fast iterators, as they fail quickly and cleanly, rather that risking arbitrary, non-deterministic behavior at an undetermined time in the future.

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