How can one get the file path of the caller functi

Question

Here is some sample code from three files:

// foo.js
var myFunc = require("./myFunc");
function foo(){
   myFunc("message");
}

// bar.js
var myFunc = require("./myFunc");
function bar(){
   myFunc("message");
}

// myFunc.js
module.exports = myFunc;
function myFunc(arg1){
   console.log(arg1);
   // Here I need the file path of the caller function
   // For example, "/path/to/foo.js" and "/path/to/bar.js"
}

I need to get the file path of the caller function dynamically, without any extra argument passing, for myFunc.

Answer 1

You need to fiddle with the inner workings of v8. See: the wiki entry about the JavaScript Stack Trace API.

I've based a little test on some code in a proposed commit and it seems to work. You end up with an absolute path.

// omfg.js

module.exports = omfg

function omfg() {
  var caller = getCaller()
  console.log(caller.filename)
}

// private

function getCaller() {
  var stack = getStack()

  // Remove superfluous function calls on stack
  stack.shift() // getCaller --> getStack
  stack.shift() // omfg --> getCaller

  // Return caller's caller
  return stack[1].receiver
}

function getStack() {
  // Save original Error.prepareStackTrace
  var origPrepareStackTrace = Error.prepareStackTrace

  // Override with function that just returns `stack`
  Error.prepareStackTrace = function (_, stack) {
    return stack
  }

  // Create a new `Error`, which automatically gets `stack`
  var err = new Error()

  // Evaluate `err.stack`, which calls our new `Error.prepareStackTrace`
  var stack = err.stack

  // Restore original `Error.prepareStackTrace`
  Error.prepareStackTrace = origPrepareStackTrace

  // Remove superfluous function call on stack
  stack.shift() // getStack --> Error

  return stack
}

And a test that includes omfg module:

#!/usr/bin/env node
// test.js

var omfg = require("./omfg")

omfg()

And you will get on the console the absolute path of test.js.

---

EXPLANATION

This is not so much a "node.js" issue as it is a "v8" issue.

See: Stack Trace Collection for Custom Exceptions

Error.captureStackTrace(error, constructorOpt) adds to the error parameter a stack property, which evaluates by default to a String (by way of FormatStackTrace). If Error.prepareStackTrace(error, structuredStackTrace) is a Function, then it is called instead of FormatStackTrace.

So, we can override Error.prepareStackTrace with our own function that will return whatever we want--in this case, just the structuredStackTrace parameter.

Then, structuredStackTrace[1].receiver is an object representing the caller.

Answer 2

You can make use of caller-callsite package:

console.log(callerCallsite().getFileName());

The alternatives are callsites and stackman packages. callsites provides you with all call sites ("stack frame" in v8 terminology). And stackman gives the call sites decorated with custom functions and behavior. Source context, among other things. Which is lines of code surrounding call site line. Also it makes use of source maps if available.

The issue with stackman is that it returns call sites asynchronously. Which is not particularly usable when running from debugger.

Here's some code I used which you might find useful:

var callsites = require('callsites');
var util = require('util');
var path = require('path');
function printStackTrace() {
    callsites().slice(1).forEach(function(cs) {
        printCallSite(cs);
    });
}
function printCallSite(cs) {
    console.log(util.format('%s:%i',
        path.relative(process.cwd(), cs.getFileName()),
        cs.getLineNumber()));
    console.log('  getTypeName(): ' + cs.getTypeName());
    console.log('  getFunctionName(): ' + cs.getFunctionName());
    console.log('  getMethodName(): ' + cs.getMethodName());
    // console.log('  getEvalOrigin(): ' + cs.getEvalOrigin());
    // console.log('  isTopLevel(): ' + (cs.isTopLevel ? cs.isTopLevel() : null));
    // console.log('  isEval(): ' + cs.isEval());
    // console.log('  isNative(): ' + cs.isNative());
    // console.log('  isConstructor(): ' + cs.isConstructor());
}
function getCallSiteIndexes(cond) {
    var cond = cond || function() { return true; };
    var options = arguments[1] || {};
    var css = options['callsites'] || callsites().slice(1);
    var r = [];
    for (var i = 0; i < css.length; i++) {
        var cs = css[i];
        if (cond(cs)) {
            if (options['first'])
                return i;
            r.push(i);
        }
    }
    return options['first'] ? null : r;
}
function getFirstCallSiteIndex(cond) {
    var css = callsites().slice(1);
    return getCallSiteIndexes(cond, {first: true, callsites: css});
}
function getCallSites(cond) {
    var options = arguments[1] || {};
    var css = options['callsites'] || callsites().slice(1);
    var indexes = getCallSiteIndexes(cond,
        Object.assign({}, {callsites: css}, options));
    if (options['first'])
        return css[indexes];
    return indexes.map(function(i) {
        return css[i];
    });
}
function getFirstCallSite(cond) {
    var css = callsites().slice(1);
    return getCallSites(cond, {first: true, callsites: css});
}

fucntion f() {
    var firstCS = callsites()[0];
    var runAsChildCSIndex = getFirstCallSiteIndex(function(cs) {
        return cs.getFileName() == firstCS.getFileName() && cs.getFunctionName() == 'Compiler.runAsChild';
    });
    if (runAsChildCSIndex) {
        printCallSite(callsites()[runAsChildCSIndex + 1]);
    } else {
        var compilerRunCS = getFirstCallSite(function(cs) {
            return cs.getFileName() == firstCS.getFileName() && cs.getFunctionName() == 'Compiler.run';
        });
        printCallSite(compilerRunCS);
    }
    ...

Answer 3

My 2 cents:

Let's say you have a log object which adds as extra information to the console the filename of the caller, for example log responds to log.info(msg) and will do something similar to:

// my_module.js
log.info('hello')
$> [[my_module.js]] hello

info would be:

info: function(msg) {
  let caller = path.basename(module.parent.filename);
  console.log(`[[${caller}]] ${msg}`);
}

Problem: as said before, parent.filename will return you who did require the module in first place, not the caller itself.

Alternative: stack-trace is a module which will do the trick:

const stackTrace = require('stack-trace');
...
info: function(msg) {
  let caller = path.basename(stackTrace.get()[0].getFilename());
  console.log(`[[${caller}]] ${msg}`);
}

The point: stackTrace.get()[0] returns the last Caller which responds to (just some of them)

• getFileName()
• getColumnNumber()
• getFunctionName()
• getLineNumber()
• getMethodName()

Answer 4

Or instead of fiddling with inner workings of the V8 engine, you use module.parent.filename to get absolute path to the module that required your module. As demonstrated here: https://gist.github.com/capaj/a9ba9d313b79f1dcd9a2

Just keep in mind that modules are cached, so if any other file requires it and calls it, it will always be the path to the first importer.